Given a list of integers, the task is to find N largest elements assuming size of list is greater than or equal o N.

**Examples :**

Input : [4, 5, 1, 2, 9] N = 2 Output : [9, 5] Input : [81, 52, 45, 10, 3, 2, 96] N = 3 Output : [81, 96, 52]

A simple solution traverse the given list N times. In every traversal, find the maximum, add it to result, and remove it from the list. Below is the implementation :

`# Python program to find N largest` `# element from given list of integers` ` ` `# Function returns N largest elements` `def` `Nmaxelements(list1, N):` ` ` `final_list ` `=` `[]` ` ` ` ` `for` `i ` `in` `range` `(` `0` `, N): ` ` ` `max1 ` `=` `0` ` ` ` ` `for` `j ` `in` `range` `(` `len` `(list1)): ` ` ` `if` `list1[j] > max1:` ` ` `max1 ` `=` `list1[j];` ` ` ` ` `list1.remove(max1);` ` ` `final_list.append(max1)` ` ` ` ` `print` `(final_list)` ` ` `# Driver code` `list1 ` `=` `[` `2` `, ` `6` `, ` `41` `, ` `85` `, ` `0` `, ` `3` `, ` `7` `, ` `6` `, ` `10` `]` `N ` `=` `2` ` ` `# Calling the function` `Nmaxelements(list1, N)` |

Output :

[85, 41]

Time Complexity : O(N * size) where size is size of the given list.

Method 2:

`# Python program to find N largest` `# element from given list of integers` ` ` `l ` `=` `[` `1000` `,` `298` `,` `3579` `,` `100` `,` `200` `,` `-` `45` `,` `900` `]` `n ` `=` `4` ` ` `l.sort()` `print` `(l[` `-` `n:])` |

Output:

[-45, 100, 200, 298, 900, 1000, 3579] Find the N largest element: 4 [298, 900, 1000, 3579]

Please refer k largest(or smallest) elements in an array for more efficient solutions of this problem.

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