Python program to Extract string till first Non-Alphanumeric character
Given a string, extract all the alphanumerics before 1st occurrence of non-alphanumeric.
Input : test_str = ‘geek$s4g!!!eeks’
Output : geek
Explanation : Stopped at $ occurrence.Input : test_str = ‘ge)eks4g!!!eeks’
Output : ge
Explanation : Stopped at ) occurrence.
Method #1 : Using regex + search()
In this, search() is used to search appropriate regex() for alphanumerics, then the result is sliced till 1st occurrence of a non-alphanumeric character
Python3
# Python3 code to demonstrate working of # Extract string till first Non-Alphanumeric character# Using regex + search()import re # initializing stringtest_str = 'geeks4g!!!eeks' # printing original stringprint("The original string is : " + str(test_str)) # using start() to get 1st substringres = re.search(r'\W+', test_str).start()res = test_str[0 : res] # printing result print("The resultant string : " + str(res)) |
Output
The original string is : geeks4g!!!eeks The resultant string : geeks4g
Method #2 : Using findall()
This is yet another regex way to solve this problem. In this, we extract the 1st substring before non-alnum character by accessing the 0th index.
Python3
# Python3 code to demonstrate working of # Extract string till first Non-Alphanumeric character# Using findall()import re # initializing stringtest_str = 'geeks4g!!!eeks' # printing original stringprint("The original string is : " + str(test_str)) # using findall() to get all substrings # 0th index gives 1st substringres = re.findall("[\dA-Za-z]*", test_str)[0] # printing result print("The resultant string : " + str(res)) |
Output
The original string is : geeks4g!!!eeks The resultant string : geeks4g
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