Given a Matrix, the task is to write a python program to extract rows with has no repeated data types.

**Examples:**

Input :test_list = [[4, 3, 1], [“gfg”, 3, {4:2}], [3, 1, “jkl”], [9, (2, 3)]]

Output :[[‘gfg’, 3, {4: 2}], [9, (2, 3)]]

Explanation :[4, 3, 1] are all integers hence omitted. [9, (2, 3)] has integer and tuple, different data types, hence included in results.

Input :test_list = [[4, 3, 1], [“gfg”, 3, {4:2}, 4], [3, 1, “jkl”], [9, (2, 3)]]

Output :[[9, (2, 3)]]

Explanation :[4, 3, 1] are all integers hence omitted. [9, (2, 3)] has integer and tuple, different data types, hence included in results.

**Method : Using ****type()**** + ****list comprehension**

In this, we use type() to check for data types of each element of rows, and if the data type repeats, the row is not included in the result.

## Python3

`# Python3 code to demonstrate working of` `# Distinct Data Type Rows` `# Using type() + list comprehension` ` ` `# initializing list` `test_list ` `=` `[[` `4` `, ` `3` `, ` `1` `], [` `"gfg"` `, ` `3` `, {` `4` `: ` `2` `}], [` `3` `, ` `1` `, ` `"jkl"` `], [` `9` `, (` `2` `, ` `3` `)]]` ` ` `# printing original list` `print` `(` `"The original list is : "` `+` `str` `(test_list))` ` ` `res ` `=` `[]` `for` `sub ` `in` `test_list:` ` ` ` ` `# get Distinct types size` ` ` `type_size ` `=` `len` `(` `list` `(` `set` `([` `type` `(ele) ` `for` `ele ` `in` `sub])))` ` ` ` ` `# if equal get result` ` ` `if` `len` `(sub) ` `=` `=` `type_size:` ` ` `res.append(sub)` ` ` `# printing result` `print` `(` `"The Distinct data type rows : "` `+` `str` `(res))` |

**Output:**

The original list is : [[4, 3, 1], [‘gfg’, 3, {4: 2}], [3, 1, ‘jkl’], [9, (2, 3)]]

The Distinct data type rows : [[‘gfg’, 3, {4: 2}], [9, (2, 3)]]

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