Given a number n. The task is to create an OTP by squaring and concatenating the odd digits of the number.

**Examples:**

Input:4365188Output:9256Input:123456Output:4163

**Explanation: **In the First example, the integers at odd places are 3, 5, and 8. So we have to return a 4 digit OTP by squaring the digits. The square of the above digits are 9, 25, 65 so the OTP to be returned is the first four digits 9256.

**Approach:** Iterate through the length of the string (number) with the starting index as 1 and taking the step as 2. Initialize an empty string and then concatenate the squares of the odd digit to that string. Finally, return the first four characters of the string as an OTP.

Below is the implementation.

`# python program to generate` `# an OTP from the squares of the` `# odd digits` ` ` ` ` `def` `OTP(number):` ` ` ` ` `# Finding the length ` ` ` `# of the string` ` ` `length ` `=` `len` `(number)` ` ` ` ` `# Declaring an empty string ` ` ` `# for storing otp` ` ` `otp ` `=` `''` ` ` ` ` `# Iterating from index 1 ` ` ` `# with step as 2` ` ` `for` `odd ` `in` `range` `(` `1` `, length, ` `2` `):` ` ` ` ` `# Concatenating the output` ` ` `# to the string ` ` ` `otp` `+` `=` `str` `(` `int` `(number[odd])` `*` `*` `2` `)` ` ` ` ` `print` `(otp[` `0` `:` `4` `])` ` ` `# Driver code` `number ` `=` `'4365188'` `OTP(number)` |

**Output:**

9256

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