Given a Tuple. The task is to convert it to List by adding the given string after every element.
Examples:
Input : test_tup = (5, 6, 7), K = "Gfg" Output : [5, 'Gfg', 6, 'Gfg', 7, 'Gfg'] Explanation : Added "Gfg" as succeeding element. Input : test_tup = (5, 6), K = "Gfg" Output : [5, 'Gfg', 6, 'Gfg'] Explanation : Added "Gfg" as succeeding element.
Method #1: Using list comprehension
In this, we construct a tuple of each element of tuple with a succeeding element and then run a nested loop to flatten each constructed tuple using list comprehension.
Python3
# Python3 code to demonstrate working of# Convert tuple to List with succeeding element# Using list comprehension # initializing tupletest_tup = (5, 6, 7, 4, 9) # printing original tupleprint("The original tuple is : ", test_tup) # initializing KK = "Gfg" # list comprehension for nested loop for flattenres = [ele for sub in test_tup for ele in (sub, K)] # printing resultprint("Converted Tuple with K : ", res) |
Output:
The original tuple is : (5, 6, 7, 4, 9)
Converted Tuple with K : [5, ‘Gfg’, 6, ‘Gfg’, 7, ‘Gfg’, 4, ‘Gfg’, 9, ‘Gfg’]
Method #2 : Using chain.from_iterable() + list() + generator expression
This is similar to above method, difference is that nested loop is avoided by flattenning using chain.from_iterable().
Python3
# Python3 code to demonstrate working of# Convert tuple to List with succeeding element# Using chain.from_iterable() + list() + generator expressionfrom itertools import chain # initializing tupletest_tup = (5, 6, 7, 4, 9) # printing original tupleprint("The original tuple is : ", test_tup) # initializing KK = "Gfg" # list comprehension for nested loop for flattenres = list(chain.from_iterable((ele, K) for ele in test_tup)) # printing resultprint("Converted Tuple with K : ", res) |
Output:
The original tuple is : (5, 6, 7, 4, 9)
Converted Tuple with K : [5, ‘Gfg’, 6, ‘Gfg’, 7, ‘Gfg’, 4, ‘Gfg’, 9, ‘Gfg’]
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