Given a python dictionary, the task si to count even and odd numbers present in the dictionary.

**Examples:**

Input: {‘a’: 1, ‘b’: 2, ‘c’: 3, ‘d’: 4, ‘e’ : 5}Output: Even = 2, odd = 3

Input: {‘x’: 4, ‘y’:9, ‘z’:16}Output: Even = 2, odd = 1

**Approach using ****values()**** Function: **Traverse the dictionary and extract its elements using values() function and for each extracted value, check if it is even or odd. Finally, print the respective counts.

## Python3

`# Python3 Program to count even and` `# odd numbers present in a dictionary` ` ` `# Function to count even and odd` `# numbers present in a dictionary` `def` `countEvenOdd(` `dict` `):` ` ` ` ` `# Stores count of even` ` ` `# and odd elements` ` ` `even ` `=` `0` ` ` `odd ` `=` `0` ` ` ` ` `# Traverse the dictionary` ` ` `for` `i ` `in` `dict` `.values():` ` ` ` ` `if` `i ` `%` `2` `=` `=` `0` `:` ` ` `even ` `=` `even ` `+` `1` ` ` `else` `:` ` ` `odd ` `=` `odd ` `+` `1` ` ` ` ` `print` `(` `"Even Count: "` `, even)` ` ` `print` `(` `"Odd Count: "` `, odd)` ` ` `# Driver Code` ` ` `dict` `=` `{` `'a'` `: ` `1` `, ` `'b'` `: ` `2` `, ` `'c'` `: ` `3` `, ` `'d'` `: ` `4` `, ` `'e'` `: ` `5` `}` `countEvenOdd(` `dict` `)` |

**Output:**

Even Count: 2 Odd Count: 3

**Time Complexity: **O(N)**Auxiliary Space:** O(1)

**Alternate Approach:** Iterate over each item in the dictionary, and for each element, check if it is even or odd. Finally, print the respective counts.

## Python3

`# Python3 Program to count even` `# and odd elements in a dictionary` ` ` `# Function to count even and` `# odd elements in a dictionary` `def` `countEvenOdd(` `dict` `):` ` ` `even ` `=` `0` ` ` `odd ` `=` `0` ` ` ` ` `# Iterate over the dictionary` ` ` `for` `i ` `in` `dict` `:` ` ` ` ` `# If current element is even` ` ` `if` `dict` `[i] ` `%` `2` `=` `=` `0` `:` ` ` ` ` `# Increase count of even` ` ` `even ` `=` `even ` `+` `1` ` ` ` ` `# Otherwise` ` ` `else` `:` ` ` ` ` `# Increase count of odd` ` ` `odd ` `=` `odd ` `+` `1` ` ` ` ` `print` `(` `"Even count: "` `, even)` ` ` `print` `(` `"Odd count: "` `, odd)` ` ` `# Driver Code` ` ` `# Given Dictionary` `dict` `=` `{` `'a'` `: ` `1` `, ` `'b'` `: ` `2` `, ` `'c'` `: ` `3` `, ` `'d'` `: ` `4` `, ` `'e'` `: ` `5` `}` ` ` `countEvenOdd(` `dict` `)` |

**Output:**

Even count: 2 Odd count: 3

**Time Complexity: **O(N)**Auxiliary Space:** O(1)

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