Given a String, the following program converts the alphabetic character around any digit to its uppercase.
Input : test_str = ‘geeks4geeks is best1 f6or ge8eks’
Output : geekS4Geeks is besT1 F6Or gE8Ek
Explanation : S and G are uppercased as surrounded by 4.
Input : test_str = ‘geeks4geeks best1 f6or ge8eks’
Output : geekS4Geeks besT1 F6Or gE8Ek
Explanation : S and G are uppercased as surrounded by 4.
Method 1 : Using upper(), loop and isdigit()
In this, we iterate for each character, check whether it’s a digit and if it is then, transform the surrounding alphabets(next and previous) to uppercase using upper().
Python3
# initializing stringtest_str = 'geeks4geeks is best1 for ge8eks' # printing original stringprint("The original string is : " + str(test_str)) res = ''for idx in range(len(test_str) - 1): if test_str[idx + 1].isdigit() or test_str[idx - 1].isdigit(): res += test_str[idx].upper() else: res += test_str[idx] # printing result print("Transformed String : " + str(res)) |
Output:
The original string is : geeks4geeks is best1 for ge8eks
Transformed String : geekS4Geeks is besT1 for gE8Ek
Method 2 : Using list comprehension
This is similar to above method, only difference being that the following tackles the same problem in a single line.
Python3
# initializing stringtest_str = 'geeks4geeks is best1 for ge8eks' # printing original stringprint("The original string is : " + str(test_str)) # list comprehension offering 1 liner solutionres = ''.join([test_str[idx].upper() if test_str[idx + 1].isdigit() or test_str[idx - 1].isdigit() else test_str[idx] for idx in range(len(test_str) - 1)]) # printing result print("Transformed String : " + str(res)) |
Output:
The original string is : geeks4geeks is best1 for ge8eks
Transformed String : geekS4Geeks is besT1 for gE8Ek
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