Given URL Parameters string, convert to dictionary items.
Input : test_str = ‘gfg=4&is=5’
Output : {‘gfg’: [‘4’], ‘is’: [‘5’]}
Explanation : gfg’s value is 4.Input : test_str = ‘gfg=4’
Output : {‘gfg’: [‘4’]}
Explanation : gfg’s value is 4 as param.
Method #1 : Using urllib.parse.parse_qs()
This is default inbuilt function which performs this task, it parses and the keys are formed from LHS of “=” and return list of values that are in RHS values for the parameters. Thus, import external urllib.parse(), to enable this to work.
Python3
# import moduleimport urllib.parse # initializing stringtest_str = 'gfg=4&is=5&best=yes' # printing original stringprint("The original string is : " + str(test_str)) # parse_qs gets the Dictionary and value listres = urllib.parse.parse_qs(test_str) # printing resultprint("The parsed URL Params : " + str(res)) |
The original string is : gfg=4&is=5&best=yes
The parsed URL Params : {‘gfg’: [‘4’], ‘is’: [‘5’], ‘best’: [‘yes’]}
Method #2 : Using findall() + setdefault()
In this, we get all the parameters using findall(), and then assign keys and values using setdefault() and loop.
Python3
import re # initializing stringtest_str = 'gfg=4&is=5&best=yes' # printing original stringprint("The original string is : " + str(test_str)) # getting all paramsparams = re.findall(r'([^=&]+)=([^=&]+)', test_str) # assigning keys with valuesres = dict()for key, val in params: res.setdefault(key, []).append(val) # printing resultprint("The parsed URL Params : " + str(res)) |
The original string is : gfg=4&is=5&best=yes
The parsed URL Params : {‘gfg’: [‘4’], ‘is’: [‘5’], ‘best’: [‘yes’]}
Attention geek! Strengthen your foundations with the Python Programming Foundation Course and learn the basics.
To begin with, your interview preparations Enhance your Data Structures concepts with the Python DS Course.
