Python program to convert URL Parameters to Dictionary items
Given URL Parameters string, convert to dictionary items.
Input : test_str = ‘gfg=4&is=5’
Output : {‘gfg’: [‘4’], ‘is’: [‘5’]}
Explanation : gfg’s value is 4.Input : test_str = ‘gfg=4’
Output : {‘gfg’: [‘4’]}
Explanation : gfg’s value is 4 as param.
Method #1 : Using urllib.parse.parse_qs()
This is default inbuilt function which performs this task, it parses and the keys are formed from LHS of “=” and return list of values that are in RHS values for the parameters. Thus, import external urllib.parse(), to enable this to work.
Python3
# import moduleimport urllib.parse # initializing stringtest_str = 'gfg=4&is=5&best=yes' # printing original stringprint("The original string is : " + str(test_str)) # parse_qs gets the Dictionary and value listres = urllib.parse.parse_qs(test_str) # printing resultprint("The parsed URL Params : " + str(res)) |
The original string is : gfg=4&is=5&best=yes
The parsed URL Params : {‘gfg’: [‘4’], ‘is’: [‘5’], ‘best’: [‘yes’]}
Method #2 : Using findall() + setdefault()
In this, we get all the parameters using findall(), and then assign keys and values using setdefault() and loop.
Python3
import re # initializing stringtest_str = 'gfg=4&is=5&best=yes' # printing original stringprint("The original string is : " + str(test_str)) # getting all paramsparams = re.findall(r'([^=&]+)=([^=&]+)', test_str) # assigning keys with valuesres = dict()for key, val in params: res.setdefault(key, []).append(val) # printing resultprint("The parsed URL Params : " + str(res)) |
The original string is : gfg=4&is=5&best=yes
The parsed URL Params : {‘gfg’: [‘4’], ‘is’: [‘5’], ‘best’: [‘yes’]}
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