Given a List, the task here is to write a python program that can split the list into list of lists using by a step value here denoted via K.
Input : test_list = [5, 6, 3, 2, 7, 1, 9, 10, 8], K = 3
Output : [[5, 2, 9], [6, 7, 10], [3, 1, 8]]
Explanation : 5, 2 and 9 are 0th, 3rd and 6th element respectively, and hence ( difference 3 ) grouped together.
Input : test_list = [5, 6, 3, 2, 7, 1], K = 3
Output : [[5, 2], [6, 7], [3, 1]]
Explanation : 5 and 2 are 0th and 3rd element respectively, and hence ( difference 3 ) grouped together.
Method 1 : Using loop and slicing
In this, loop is employed to skip numbers as required, and each subsequent skipped sliced list is extracted using slicing and is appended to result.
Example:
Python3
# initializing list test_list = [5, 6, 3, 2, 7, 1, 9, 10, 8] # printing original list print("The original list is : " + str(test_list)) # initializing skips K = 3 res = [] for idx in range(0, K): # 3rd arg. of slicing skips by K res.append(test_list[idx::K]) # printing result print("Stepped splitted List : " + str(res)) |
Output:
The original list is : [5, 6, 3, 2, 7, 1, 9, 10, 8]
Stepped splitted List : [[5, 2, 9], [6, 7, 10], [3, 1, 8]]
Method 2 : Using list comprehension and slicing
Similar to above method, only difference being usage of list comprehension for task of iteration instead of loop for shorthand alternative.
Example:
Python3
# initializing list test_list = [5, 6, 3, 2, 7, 1, 9, 10, 8] # printing original list print("The original list is : " + str(test_list)) # initializing skips K = 3 # list comprehension used as one liner res = [test_list[idx::K] for idx in range(0, K)] # printing result print("Stepped splitted List : " + str(res)) |
Output:
The original list is : [5, 6, 3, 2, 7, 1, 9, 10, 8]
Stepped splitted List : [[5, 2, 9], [6, 7, 10], [3, 1, 8]]
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