Python | Program to accept the strings which contains all vowels
Given a string, the task is to check if every vowel is present or not. We consider a vowel to be present if it is present in upper case or lower case. i.e. ‘a’, ‘e’, ‘i’.’o’, ‘u’ or ‘A’, ‘E’, ‘I’, ‘O’, ‘U’ .
Input : geeksforgeeks Output : Not Accepted All vowels except 'o' are not present Input : ABeeIghiObhkUul Output : Accepted All vowels are present
Approach : Firstly, create set of vowels using set() function. Check for each character of the string is vowel or not, if vowel then add into the set s. After coming out of the loop, check length of the set s, if length of set s is equal to the length of the vowels set then string is accepted otherwise not.
Below is the implementation :
Alternate Implementation :
Alternate Implementation 2.0 :
Alternate Implementation 3.0 (Using Regular Expressions):
- Compile a regular expression using compile() for “character is not a, e, i, o and u”.
- Use re.findall() to fetch the strings satisfying the above regular expression.
- Print output based on the result.
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