Given two list, one will be used to provide keys to dictionary and the other for values. The following program takes K values from second list and assigns it to each key, creating a dictionary of the following kind:
Input : test_list = [“gfg”, “best”], val_list = [1, 4, 5, 6, 7, 8, 8, 5], K = 4
Output : {‘gfg’: [1, 4, 5, 6], ‘best’: [7, 8, 8, 5]}
Explanation : Equal elements paired to each key.
Input : test_list = [“gfg”], val_list = [1, 4, 5, 6], K = 4
Output : {‘gfg’: [1, 4, 5, 6]}
Explanation : All elements assigned to only key.
Method : Using loop and slicing
Python3
from collections import defaultdict # initializing listtest_list = ["gfg", "is", "best", "good"] # printing original listprint("The original list is : " + str(test_list)) # initializing values list val_list = [1, 4, 5, 6, 7, 8, 8, 5, 4] # initializing K K = 2 # work listval_list = val_list[:(len(test_list) * K)] # gets requried dictionary list res = defaultdict(list)key_cnt = 0for idx in range(0, len(val_list)): # append values to required keys res[test_list[key_cnt]].append(val_list[idx]) # increment keys when K if (idx + 1) % K == 0: key_cnt += 1 # printing result print("The constructed dictionary : " + str(dict(res))) |
Output:
The original list is : [‘gfg’, ‘is’, ‘best’, ‘good’]
The constructed dictionary : {‘gfg’: [1, 4], ‘is’: [5, 6], ‘best’: [7, 8], ‘good’: [8, 5]}
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