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Python | Program that matches a word containing ‘g’ followed by one or more e’s using regex

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  • Difficulty Level : Basic
  • Last Updated : 29 Dec, 2020

Prerequisites : Regular Expressions | Set 1, Set 2

Given a string, the task is to check if that string contains any g followed by one or more e’s in it, otherwise, print No match.

Examples :

Input : geeks for geeks
Output : geeks 
         geeks

Input : graphic era
Output : No match 

Approach : Firstly, make a regular expression (regex) object that matches a word which contains ‘g’ followed by one or more e’s, then pass a string in the findall method. This method returns the list of the matched strings. Loop through the list and print each matched word.

\w – represent Any letter, numeric digit, or the underscore character.
* means zero or more occurrence of the character.
+ means one or more occurrence of the character.

Below is the implementation :




# Python program that matches a word
# containing ‘g’ followed by one or
# more e’s using regex
  
# import re packages
import re
  
# Function check if the any word of
# the string containing 'g' followed
# by one or more e's
def check(string) :
  
      
    # Regex \w * ge+\w * will match 
    # text that contains 'g', followed 
    # by one or more 'e'
    regex = re.compile("ge+\w*")
  
    # The findall() method returns all 
    # matching strings of the regex pattern
    match_object = regex.findall(string)
  
    # If length of match_object is not
    # equal to zero then it contains
    # matched string
    if len(match_object) != 0 :
  
        # looping through the list
        for word in match_object :
            print(word)
              
    else :
        print("No match")
  
  
# Driver Code     
if __name__ == '__main__' :
  
    # Enter the string
    string = "Welcome to geeks for geeks"
  
    # Calling check function
    check(string)

Output :

geeks
geeks

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