Python | Program that matches a word containing 'g' followed by one or more e's using regex

Prerequisites : Regular Expressions | Set 1, Set 2

Given a string, the task is to check if that string contains any g followed by one or more e’s in it, otherwise, print No match.

Examples :

Input : geeks for geeks
Output : geeks 
         geeks

Input : graphic era
Output : No match

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach : Firstly, make a regular expression (regex) object that matches a word which contains ‘g’ followed by one or more e’s, then pass a string in the findall method. This method returns the list of the matched strings. Loop through the list and print each matched word.

\w – represent Any letter, numeric digit, or the underscore character.
* means zero or more occurrence of the character.
+ means one or more occurrence of the character.

Below is the implementation :

# Python program that matches a word 
# containing ‘g’ followed by one or 
# more e’s using regex 
  
# import re pakages 
import re 
  
# Function check if the any word of 
# the string containing 'g' followed 
# by one or more e's 
def check(string) : 
  
      
    # Regex \w * ge+\w * will match  
    # text that contains 'g', followed  
    # by one or more 'e' 
    regex = re.compile("ge+\w*") 
  
    # The findall() method returns all  
    # matching strings of the regex pattern 
    match_object = regex.findall(string) 
  
    # If lenght of match_object is not 
    # equal to zero then it contains 
    # matched string 
    if len(match_object) != 0 : 
  
        # looping throgh the list 
        for word in match_object : 
            print(word) 
              
    else : 
        print("No match") 
  
  
# Driver Code      
if __name__ == '__main__' : 
  
    # Enter the string 
    string = "Welcome to geeks for geeks"
  
    # Calling check function 
    check(string) 