Given two matrix the task is that we will have to create a program to multiply two matrices in python.
Examples:
Input : X = [[1, 7, 3],
[3, 5, 6],
[6, 8, 9]]
Y = [[1, 1, 1, 2],
[6, 7, 3, 0],
[4, 5, 9, 1]]
Output : [55, 65, 49, 5]
[57, 68, 72, 12]
[90, 107, 111, 21]
Using Simple Nested Loops: In this program we have to use nested for loops to iterate through each row and each column.
Implementation:
fdfxfxddx
Output:
[114, 160, 60, 27]
[74, 97, 73, 14]
[119, 157, 112, 23]
Time Complexity: O(M*M*N), as we are using nested loop traversing, M*M*N.
Auxiliary Space: O(M*N), as we are using a result matrix which is extra space.
Method 2: Matrix Multiplication Using Nested List. We use zip in Python.
Implementation:
Python3
A = [[ 12 , 7 , 3 ],
[ 4 , 5 , 6 ],
[ 7 , 8 , 9 ]]
B = [[ 5 , 8 , 1 , 2 ],
[ 6 , 7 , 3 , 0 ],
[ 4 , 5 , 9 , 1 ]]
result = [[ sum (a * b for a, b in zip (A_row, B_col))
for B_col in zip ( * B)]
for A_row in A]
for r in result:
print (r)
|
Output:
[114, 160, 60, 27]
[74, 97, 73, 14]
[119, 157, 112, 23]
Time Complexity: O(M*M*N), as we are using nested loop traversing, M*M*N.
Auxiliary Space: O(M*N), as we are using a result matrix which is extra space.
Method 3: Matrix Multiplication (Vectorized implementation).
Implementation:
Python3
import numpy as np
A = [[ 12 , 7 , 3 ],
[ 4 , 5 , 6 ],
[ 7 , 8 , 9 ]]
B = [[ 5 , 8 , 1 , 2 ],
[ 6 , 7 , 3 , 0 ],
[ 4 , 5 , 9 , 1 ]]
result = [[ 0 , 0 , 0 , 0 ],
[ 0 , 0 , 0 , 0 ],
[ 0 , 0 , 0 , 0 ]]
result = np.dot(A,B)
for r in result:
print (r)
|
Output:
[114, 160, 60, 27]
[74, 97, 73, 14]
[119, 157, 112, 23]
Time Complexity: O(M*M*N), as we are using nested loop traversing, M*M*N.
Auxiliary Space: O(M*N), as we are using a result matrix which is extra space.
Method 4:Using recursive matrix multiplication:
Algorithm:
- Check if the dimensions of the two input matrices are valid for multiplication. If the number of columns in the first matrix does not equal the number of rows in the second matrix, then they cannot be multiplied. In this case, raise an error or return a None object.
- Check if the matrices are of size 1×1. If they are, multiply their elements and return the result.
- If the matrices are not of size 1×1, divide each matrix into four submatrices of equal size.
- Recursively multiply the submatrices using the same algorithm, until each submatrix is of size 1×1.
- Compute the product of the resulting submatrices using the formula:
- result = [A11B11 + A12B21, A11B12 + A12B22, A21B11 + A22B21, A21B12 + A22B22]
- Return the resulting matrix.
Python3
def matrix_multiply_recursive(A, B):
if len (A[ 0 ]) ! = len (B):
raise ValueError( "Invalid matrix dimensions" )
result = [[ 0 for j in range ( len (B[ 0 ]))] for i in range ( len (A))]
def multiply(A, B, result, i, j, k):
if i > = len (A):
return
if j > = len (B[ 0 ]):
return multiply(A, B, result, i + 1 , 0 , 0 )
if k > = len (B):
return multiply(A, B, result, i, j + 1 , 0 )
result[i][j] + = A[i][k] * B[k][j]
multiply(A, B, result, i, j, k + 1 )
multiply(A, B, result, 0 , 0 , 0 )
return result
A = [[ 12 , 7 , 3 ], [ 4 , 5 , 6 ], [ 7 , 8 , 9 ]]
B = [[ 5 , 8 , 1 , 2 ], [ 6 , 7 , 3 , 0 ], [ 4 , 5 , 9 , 1 ]]
result = matrix_multiply_recursive(A, B)
for row in result:
print (row)
|
Output
[114, 160, 60, 27]
[74, 97, 73, 14]
[119, 157, 112, 23]
Time complexity: O(n^3)
Auxiliary Space : O(n^2)
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Last Updated :
28 Jul, 2023
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