# Python Program For Removing Every K-th Node Of The Linked List

• Last Updated : 18 May, 2022

Given a singly linked list, Your task is to remove every K-th node of the linked list. Assume that K is always less than or equal to length of Linked List.
Examples :

```Input: 1->2->3->4->5->6->7->8
k = 3
Output: 1->2->4->5->7->8
As 3 is the k-th node after its deletion list
would be 1->2->4->5->6->7->8
And now 4 is the starting node then from it, 6
would be the k-th node. So no other kth node
could be there.So, final list is:
1->2->4->5->7->8.

Input: 1->2->3->4->5->6
k = 1
Output: Empty list
All nodes need to be deleted```

The idea is to traverse the list from the beginning and keep track of nodes visited after the last deletion. Whenever count becomes k, delete the current node and reset the count as 0.

```Traverse list and do following
(a) Count node before deletion.
(b) If (count == k) that means current
node is to be deleted.
(i)  Delete current node i.e. do

//  assign address of next node of
// current node to the previous node
// of the current node.
prev->next = ptr->next i.e.

(ii) Reset count as 0, i.e., do count = 0.
(c) Update prev node if count != 0 and if
count is 0 that means that node is a
starting point.
(d) Update ptr and continue until all
k-th node gets deleted.```

Below is the implementation.

## Python3

 `# Python3 program to delete every ``# k-th Node of a singly linked list.``import` `math`` ` `# Linked list Node ``class` `Node: ``    ``def` `__init__(``self``, data): ``        ``self``.data ``=` `data ``        ``self``.``next` `=` `None`` ` `# To remove complete list (Needed ``# for case when k is 1)``def` `freeList(node):``    ``while` `(node !``=` `None``):``        ``next` `=` `node.``next``        ``node ``=` `next``    ``return` `node`` ` `# Deletes every k-th node and ``# returns head of modified list.``def` `deleteKthNode(head, k):``     ` `    ``# If linked list is empty``    ``if` `(head ``=``=` `None``):``        ``return` `None`` ` `    ``if` `(k ``=``=` `1``):``        ``freeList(head)``        ``return` `None``     ` `    ``# Initialize ptr and prev before ``    ``# starting traversal.``    ``ptr ``=` `head``    ``prev ``=` `None`` ` `    ``# Traverse list and delete every ``    ``# k-th node``    ``count ``=` `0``    ``while` `(ptr !``=` `None``):``         ` `        ``# Increment Node count``        ``count ``=` `count ``+` `1`` ` `        ``# Check if count is equal to k``        ``# if yes, then delete current Node``        ``if` `(k ``=``=` `count):``             ` `            ``# Put the next of current Node in``            ``# the next of previous Node``            ``# delete(prev.next)``            ``prev.``next` `=` `ptr.``next`` ` `            ``# Set count = 0 to reach further``            ``# k-th Node``            ``count ``=` `0``         ` `        ``# Update prev if count is not 0``        ``if` `(count !``=` `0``):``            ``prev ``=` `ptr`` ` `        ``ptr ``=` `prev.``next``     ` `    ``return` `head`` ` `# Function to print linked list ``def` `displayList(head):``    ``temp ``=` `head``    ``while` `(temp !``=` `None``):``        ``print``(temp.data, ``              ``end ``=` `' '``)``        ``temp ``=` `temp.``next``     ` `# Utility function to create ``# a new node.``def` `newNode( x):``    ``temp ``=` `Node(x)``    ``temp.data ``=` `x``    ``temp.``next` `=` `None``    ``return` `temp`` ` `# Driver Code``if` `__name__``=``=``'__main__'``: ``     ` `    ``# Start with the empty list ``    ``head ``=` `newNode(``1``)``    ``head.``next` `=` `newNode(``2``)``    ``head.``next``.``next` `=` `newNode(``3``)``    ``head.``next``.``next``.``next` `=` `newNode(``4``)``    ``head.``next``.``next``.``next``.``next` `=` `    ``newNode(``5``)``    ``head.``next``.``next``.``next``.``next``.``next` `=` `    ``newNode(``6``)``    ``head.``next``.``next``.``next``.``next``.``next``.``next` `=` `    ``newNode(``7``)``    ``head.``next``.``next``.``next``.``next``.``next``.``next``.``next` `=` `    ``newNode(``8``)`` ` `    ``k ``=` `3``    ``head ``=` `deleteKthNode(head, k)`` ` `    ``displayList(head)``# This code is contributed by Srathore`

Output:

`1 2 4 5 7 8`

Time Complexity: O(n)

Please refer complete article on Remove every k-th node of the linked list for more details!

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