Given a singly linked list, write a function to swap elements pairwise.
Input: 1->2->3->4->5->6->NULL
Output: 2->1->4->3->6->5->NULL
Input: 1->2->3->4->5->NULL
Output: 2->1->4->3->5->NULL
Input: 1->NULL
Output: 1->NULL
For example, if the linked list is 1->2->3->4->5 then the function should change it to 2->1->4->3->5, and if the linked list is then the function should change it to.
METHOD (Iterative):
Start from the head node and traverse the list. While traversing swap data of each node with its next node’s data.
Below is the implementation of the above approach:
Python
class Node:
def __init__( self , data):
self .data = data
self . next = None
class LinkedList:
def __init__( self ):
self .head = None
def pairwiseSwap( self ):
temp = self .head
if temp is None :
return
while (temp and temp. next ):
if (temp.data ! = temp. next .data):
temp.data, temp. next .data = temp. next .data, temp.data
temp = temp. next . next
def push( self , new_data):
new_node = Node(new_data)
new_node. next = self .head
self .head = new_node
def printList( self ):
temp = self .head
while (temp):
print temp.data,
temp = temp. next
llist = LinkedList()
llist.push( 5 )
llist.push( 4 )
llist.push( 3 )
llist.push( 2 )
llist.push( 1 )
print "Linked list before calling pairWiseSwap() "
llist.printList()
llist.pairwiseSwap()
print "Linked list after calling pairWiseSwap()"
llist.printList()
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Output:
Linked list before calling pairWiseSwap()
1 2 3 4 5
Linked list after calling pairWiseSwap()
2 1 4 3 5
Time complexity: O(n)
Auxiliary Space: O(1)
Please refer complete article on Pairwise swap elements of a given linked list for more details!