Python Program for GCD of more than two (or array) numbers
The GCD of three or more numbers equals the product of the prime factors common to all the numbers, but it can also be calculated by repeatedly taking the GCDs of pairs of numbers.
gcd(a, b, c) = gcd(a, gcd(b, c))
= gcd(gcd(a, b), c)
= gcd(gcd(a, c), b)
Time complexity : O(n + log(min(a, b))), as the function goes through the list of numbers and finds the GCD for each pair of numbers using the Euclidean algorithm.
Auxiliary Space: O(log x), as the function only uses a few variables to store the GCD and the numbers being compared.
Please refer complete article on GCD of more than two (or array) numbers for more details!