Python | Product of Squares in List
Python being the language of magicians can be used to perform many tedious and repetitive tasks in a easy and concise manner and having the knowledge to utilize this tool to the fullest is always useful. One such small application can be finding product of squares of list in just one line. Let’s discuss certain ways in which this can be performed.
Method #1 : Using reduce() + lambda
The power of lambda functions to perform lengthy tasks in just one line, allows it combined with reduce which is used to accumulate the subproblem, to perform this task as well. Works with only Python 2.
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# Python code to demonstrate # Product of Squares in List# using reduce() + lambda # initializing listtest_list = [3, 5, 7, 9, 11] # printing original list print ("The original list is : " + str(test_list)) # using reduce() + lambda# Product of Squares in Listres = reduce(lambda i, j: i * j*j, [test_list[:1][0]**2]+test_list[1:]) # printing resultprint ("The product of squares of list is : " + str(res)) |
The original list is : [3, 5, 7, 9, 11] The product of squares of list is : 108056025
Method #2 : Using map() + loop
The similar solution can also be obtained using the map function to integrate and external product function to perform the product of the squared number.
# Python3 code to demonstrate # Product of Squares in List# using sum() + max() # getting Product def prod(val) : res = 1 for ele in val: res *= ele return res # initializing listtest_list = [3, 5, 7, 9, 11] # printing original list print ("The original list is : " + str(test_list)) # using sum() + max()# Product of Squares in Listres = prod(map(lambda i : i * i, test_list)) # printing resultprint ("The product of squares of list is : " + str(res)) |
The original list is : [3, 5, 7, 9, 11] The product of squares of list is : 108056025
