# Python | Product of Squares in List

• Last Updated : 19 Feb, 2020

Python being the language of magicians can be used to perform many tedious and repetitive tasks in a easy and concise manner and having the knowledge to utilize this tool to the fullest is always useful. One such small application can be finding product of squares of list in just one line. Let’s discuss certain ways in which this can be performed.

Method #1 : Using `reduce()` + lambda
The power of lambda functions to perform lengthy tasks in just one line, allows it combined with reduce which is used to accumulate the subproblem, to perform this task as well. Works with only Python 2.

Attention geek! Strengthen your foundations with the Python Programming Foundation Course and learn the basics.

To begin with, your interview preparations Enhance your Data Structures concepts with the Python DS Course. And to begin with your Machine Learning Journey, join the Machine Learning - Basic Level Course

 `# Python code to demonstrate ``# Product of Squares in List``# using reduce() + lambda`` ` `# initializing list``test_list ``=` `[``3``, ``5``, ``7``, ``9``, ``11``]`` ` `# printing original list ``print` `(``"The original list is : "` `+` `str``(test_list))`` ` `# using reduce() + lambda``# Product of Squares in List``res ``=` `reduce``(``lambda` `i, j: i ``*` `j``*``j, [test_list[:``1``][``0``]``*``*``2``]``+``test_list[``1``:])`` ` `# printing result``print` `(``"The product of squares of list is : "` `+` `str``(res))`
Output :

```The original list is : [3, 5, 7, 9, 11]
The product of squares of list is : 108056025
```

Method #2 : Using `map() + loop`
The similar solution can also be obtained using the map function to integrate and external product function to perform the product of the squared number.

 `# Python3 code to demonstrate ``# Product of Squares in List``# using sum() + max()`` ` `# getting Product ``def` `prod(val) : ``    ``res ``=` `1` `    ``for` `ele ``in` `val: ``        ``res ``*``=` `ele ``    ``return` `res `` ` `# initializing list``test_list ``=` `[``3``, ``5``, ``7``, ``9``, ``11``]`` ` `# printing original list ``print` `(``"The original list is : "` `+` `str``(test_list))`` ` `# using sum() + max()``# Product of Squares in List``res ``=` `prod(``map``(``lambda` `i : i ``*` `i, test_list))`` ` `# printing result``print` `(``"The product of squares of list is : "` `+` `str``(res))`
Output :
```The original list is : [3, 5, 7, 9, 11]
The product of squares of list is : 108056025
```

My Personal Notes arrow_drop_up