# Python | Print unique rows in a given boolean matrix using Set with tuples

Given a binary matrix, print all unique rows of the given matrix. Order of row printing doesn’t matter.

Examples:

```Input:
mat = [[0, 1, 0, 0, 1],
[1, 0, 1, 1, 0],
[0, 1, 0, 0, 1],
[1, 1, 1, 0, 0]]
Output:
(1, 1, 1, 0, 0)
(0, 1, 0, 0, 1)
(1, 0, 1, 1, 0)
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

We have existing solution for this problem please refer link. We can solve this problem in python quickly using Set data structure. Approach is very simple.

1. We are given list of boolean values list, put all rows (list) in set because set contains unique values.
2. Since list is an unhashable type for set because it is mutable that’s why first we convert each row (list) into tuple then we put all tuple in set.
3. Resultant set will contain only unique valued tuples (row).

 `# Python program to Print unique rows in a  ` `# given boolean matrix using Set with tuples ` ` `  `# Function to print unique rows in a given boolean matrix ` ` `  `def` `uniqueRows(``input``): ` ` `  `    ``# convert each row (list) into tuple ` `    ``# we are mapping tuple function on each row of  ` `    ``# input matrix ` `    ``input` `=` `map``(``tuple``, ``input``) ` ` `  `    ``# put all rows in set ` `    ``result ``=` `set``(``input``) ` ` `  `    ``# print all unique rows ` `    ``for` `row ``in` `list``(result): ` `        ``print` `(row) ` ` `  `# Driver program ` `if` `__name__ ``=``=` `"__main__"``: ` `    ``input` `=` `[[``0``, ``1``, ``0``, ``0``, ``1``], ` `             ``[``1``, ``0``, ``1``, ``1``, ``0``], ` `             ``[``0``, ``1``, ``0``, ``0``, ``1``], ` `             ``[``1``, ``1``, ``1``, ``0``, ``0``]] ` `    ``uniqueRows(``input``) `

Output:

```(1, 1, 1, 0, 0)
(0, 1, 0, 0, 1)
(1, 0, 1, 1, 0)
```

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