Given a binary matrix, print all unique rows of the given matrix. Order of row printing doesn’t matter.

Examples:

Input: mat = [[0, 1, 0, 0, 1], [1, 0, 1, 1, 0], [0, 1, 0, 0, 1], [1, 1, 1, 0, 0]] Output: (1, 1, 1, 0, 0) (0, 1, 0, 0, 1) (1, 0, 1, 1, 0)

We have existing solution for this problem please refer link. We can solve this problem in python quickly using Set data structure. Approach is very simple.

- We are given list of boolean values list, put all rows (list) in set because set contains unique values.
- Since list is an unhashable type for set because it is mutable that’s why first we convert each row (list) into tuple then we put all tuple in set.
- Resultant set will contain only unique valued tuples (row).

`# Python program to Print unique rows in a ` `# given boolean matrix using Set with tuples ` ` ` `# Function to print unique rows in a given boolean matrix ` ` ` `def` `uniqueRows(` `input` `): ` ` ` ` ` `# convert each row (list) into tuple ` ` ` `# we are mapping tuple function on each row of ` ` ` `# input matrix ` ` ` `input` `=` `map` `(` `tuple` `, ` `input` `) ` ` ` ` ` `# put all rows in set ` ` ` `result ` `=` `set` `(` `input` `) ` ` ` ` ` `# print all unique rows ` ` ` `for` `row ` `in` `list` `(result): ` ` ` `print` `(row) ` ` ` `# Driver program ` `if` `__name__ ` `=` `=` `"__main__"` `: ` ` ` `input` `=` `[[` `0` `, ` `1` `, ` `0` `, ` `0` `, ` `1` `], ` ` ` `[` `1` `, ` `0` `, ` `1` `, ` `1` `, ` `0` `], ` ` ` `[` `0` `, ` `1` `, ` `0` `, ` `0` `, ` `1` `], ` ` ` `[` `1` `, ` `1` `, ` `1` `, ` `0` `, ` `0` `]] ` ` ` `uniqueRows(` `input` `) ` |

*chevron_right*

*filter_none*

Output:

(1, 1, 1, 0, 0) (0, 1, 0, 0, 1) (1, 0, 1, 1, 0)

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