Python | Print number of leap years from given list of years

The problem of finding leap year is quite generic and we might face the issue of finding the number of leap years in given list of years. Let’s discuss certain ways in which this can be performed.

Method #1: Using Iteration

Check whether year is a multiple of 4 and not multiple of 100 or year is multiple of 400.

# Python code to finding number of  
# leap years in list of years. 
  
# Input list initialization 
Input = [2001, 2002, 2003, 2004, 2005, 2006, 
         2007, 2008, 2009, 2010, 2011, 2012] 
  
# Find whether it is leap year or not 
def checkYear(year): 
    return (((year % 4 == 0) and
             (year % 100 != 0)) or
             (year % 400 == 0))  
   
# Answer Initialization 
Answer = 0 
  
for elem in Input: 
    if checkYear(elem): 
        Answer = Answer + 1
  
# Printing 
print("No of leap years are:", Answer) 

Output:

No of leap years are: 3

Method #2: Using calender

# Python code to finding number of  
# leap years in list of years. 
  
# Importing calender 
import calendar 
  
# Input list initialization 
Input = [2001, 2002, 2003, 2004, 2005, 
         2006, 2007, 2008, 2009, 2010] 
  
# Using calender to find leap year 
def FindLeapYear(Input): 
    ans = 0
    for elem in Input: 
        if calendar.isleap(int(elem)): 
            ans = ans + 1
    return ans 
  
Output = FindLeapYear(Input) 
  
# Printing 
print("No of leap years are:", Output) 

Output:

No of leap years are: 2

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