Given an index, remove the element at that index from the list and print the new list.
Examples:
Input : list = [10, 20, 30, 40, 50]
index = 2
Output : [10, 20, 40, 50]
Input : list = [10, 20, 40, 50]
index = 0
Output : [20, 40, 50]
Method 1: Traversal of list
Using traversal in the list, append all the index values except the given index to a new list and then print the new list. For this we will require a new list where we can append all the values except the given index value.
Below is the Python3 implementation of the above approach
# Python3 program to remove the index # element from the list # using traversal def remove(list1, pos): newlist = [] # traverse in the list for x in range(len(list1)): # if index not equal to pos if x != pos: newlist.append(list1[x]) print(*newlist) # driver codelist1 = [10, 20, 30, 40, 50]pos = 2remove(list1, pos) |
Output:
10 20 40 50
Method 2: pop()
pop() function helps us to pop the value at any desired position that is passed in the parameter, if nothing is passed in the parameter, then it removes the last index value.
Below is the Python3 implementation of the above approach:
# Python3 program to remove the index # element from the list # using pop() def remove(list1, pos): # pop the element at index = pos list1.pop(pos) print(*list1) # driver codelist1 = [10, 20, 30, 40, 50]pos = 2remove(list1, pos) |
Output:
10 20 40 50
Method 3: del function
del function can be used to remove any element at any given position. If -1 or -2 is given in the [] brackets, then it deletes the last and second last element respectively.
Below is the Python3 implementation of the above approach:
# Python3 program to remove the index element# from the list using del def remove(list1, pos): # delete the element at index = pos del list1[pos] print(*list1) # driver codelist1 = [10, 20, 30, 40, 50]pos = 2remove(list1, pos) |
Output:
10 20 40 50
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