Python | Prefix key match in dictionary

Sometimes, while working with dictionaries, we can have a problem in which we need to find the dictionary items that have some constraints on keys. One such constraint can be a prefix match on keys. Let’s discuss certain ways in which this task can be performed.

Method #1 : Using dictionary comprehension + startswith()
The combination of above two methods can be used to perform this particular task. In this, dictionary comprehension does the basic task of dictionary construction and startswith() performs the utility task of checking keys starting with specific prefix.

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# Python3 code to demonstrate working of
# Prefix key match in dictionary
# Using dictionary comprehension + startswith()
  
# Initialize dictionary
test_dict = {'tough' : 1, 'to' : 2, 'do' : 3, 'todays' : 4, 'work' : 5}
  
# printing original dictionary
print("The original dictionary : " +  str(test_dict))
  
# Initialize prefix 
test_pref = 'to'
  
# Using dictionary comprehension + startswith()
# Prefix key match in dictionary
res = {key:val for key, val in test_dict.items() 
                   if key.startswith(test_pref)}
  
# printing result 
print("Filtered dictionary keys are : " + str(res))

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Output :



The original dictionary : {‘to’: 2, ‘tough’: 1, ‘work’: 5, ‘todays’: 4, ‘do’: 3}
Filtered dictionary keys are : {‘to’: 2, ‘tough’: 1, ‘todays’: 4}

 

Method #2 : Using map() + filter() + items() + startswith()
This particular task can also be performed using the combination of above functions. The map function ties the filter logic of startswith() to each dictionary’s items extracted by items()

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# Python3 code to demonstrate working of
# Prefix key match in dictionary
# Using map() + filter() + items() + startswith()
  
# Initialize dictionary
test_dict = {'tough' : 1, 'to' : 2, 'do' : 3, 'todays' : 4, 'work' : 5}
  
# printing original dictionary
print("The original dictionary : " +  str(test_dict))
  
# Initialize prefix 
test_pref = 'to'
  
# Using map() + filter() + items() + startswith()
# Prefix key match in dictionary
res = dict(filter(lambda item: item[0].startswith(test_pref),
                                          test_dict.items()))
  
# printing result 
print("Filtered dictionary keys are : " + str(res))

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Output :

The original dictionary : {‘to’: 2, ‘tough’: 1, ‘work’: 5, ‘todays’: 4, ‘do’: 3}
Filtered dictionary keys are : {‘to’: 2, ‘tough’: 1, ‘todays’: 4}



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