Open In App
Related Articles

Python | Percentage increase in hemisphere volume if radius is increased

Improve Article
Improve
Save Article
Save
Like Article
Like

Given that the radius of a hemisphere is increased by a fixed percentage so, the target is to calculate the percentage increase in the volume of the hemisphere.
 

Examples: 
Input : 
20 
Output : 
72.8 %
Input : 
70 
Output : 
391.3 % 
 

Approach: 
Let, the radius of the hemisphere = a
Given percentage increase = x%
Volume before increase = \frac{2}{3} * 3.14*a^3
New radius after increase = a + \frac{ax}{100}
So, new volume = \frac{2}{3}*3.14*(a^3 + (\frac{ax}{100})^3 + \frac{3a^3x}{100} + \frac{3a^3x^2}{10000})
Change in volume = \frac{2}{3}*3.14*((\frac{ax}{100})^3 + \frac{3a^3x}{100} + \frac{3a^3x^2}{10000})
Percentage increase in volume = (\frac{2}{3}*3.14*((\frac{ax}{100})^3 + \frac{3a^3x}{100} + \frac{3a^3x^2}{10000})/\frac{2}{3}*3.14*a^3) * 100 = \frac{x^3}{10000} + 3x + \frac{3x^2}{100}
Below is the Python code implementation of the above mentioned approach. 
 

Python3




# Python3 program to find percentage increase
# in the volume of the hemisphere
# if the radius is increased by a given percentage
   
def newvol(x):
   
    print('percentage increase in the  volume of the hemisphere is ', pow(x, 3) / 10000 + 3 * x
                + (3 * pow(x, 2)) / 100, '%')
   
# Driver code
x = 10.0
newvol(x)


Output : 

percentage increase in the volume of the hemisphere is  33.1 %

Time Complexity: O(log x) because pow function would take logarithmic time

Auxiliary Space: O(1)

 


Feeling lost in the world of random DSA topics, wasting time without progress? It's time for a change! Join our DSA course, where we'll guide you on an exciting journey to master DSA efficiently and on schedule.
Ready to dive in? Explore our Free Demo Content and join our DSA course, trusted by over 100,000 geeks!

Last Updated : 20 Feb, 2023
Like Article
Save Article
Previous
Next
Similar Reads
Complete Tutorials