Python | Pandas TimedeltaIndex.difference

Python is a great language for doing data analysis, primarily because of the fantastic ecosystem of data-centric python packages. Pandas is one of those packages and makes importing and analyzing data much easier.

Pandas TimedeltaIndex.difference() function return a new Index with elements from the index that are not in other. This is the set difference of two Index objects. It’s sorted if sorting is possible.

Syntax : TimedeltaIndex.difference(other)



Parameters :
other : Index or array-like

Return : difference : Index

Example #1: Use TimedeltaIndex.difference() function to find the set difference of two TimedeltaIndex objects.

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# importing pandas as pd
import pandas as pd
  
# Create the first TimedeltaIndex object
tidx1 = pd.TimedeltaIndex(data =['06:05:01.000030', '+23:59:59.999999'
                                 '22 day 2 min 3us 10ns', '+23:29:59.999999'
                                                         '+12:19:59.999999'])
  
# Create the seccond TimedeltaIndex object
tidx2 = pd.TimedeltaIndex(data =['09:11:18.000030', '+23:59:59.999999',
                                 '9 day 18 min 3us ', '+23:29:59.999999',
                                                     '+12:19:59.999999'])
  
# Print the first and second TimedeltaIndex object
print(tidx1, "\n", tidx2)

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Output :

Now we will use the TimedeltaIndex.difference() function to find the set difference.

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# find the set difference
tidx1.difference(tidx2)

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Output :

As we can see in the output, the TimedeltaIndex.difference() function has returned a new object which contains only those elements which are unique to tidx1.
 
Example #2: Use TimedeltaIndex.difference() function to find the set difference of two TimedeltaIndex objects.

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# importing pandas as pd
import pandas as pd
  
# Create the first TimedeltaIndex object
tidx1 = pd.TimedeltaIndex(start ='1 days 02:00:12.001124', periods = 5,
                                              freq ='D', name ='Koala')
  
# Create the second TimedeltaIndex object
tidx2 = pd.TimedeltaIndex(start ='3 days 02:00:12.001124', periods = 5,
                                              freq ='D', name ='Koala')
  
# Print the first and second TimedeltaIndex object
print(tidx1, "\n", tidx2)

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Output :


Now we will use the TimedeltaIndex.difference() function to find the set difference.

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# find the set difference
tidx1.difference(tidx2)

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Output :

As we can see in the output, the TimedeltaIndex.difference() function has returned a new object which contains only those elements which are unique to tidx1.



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