Python | Pandas Series.aggregate()
Pandas series is a One-dimensional ndarray with axis labels. The labels need not be unique but must be a hashable type. The object supports both integer- and label-based indexing and provides a host of methods for performing operations involving the index.
Pandas Series.aggregate()
function aggregate using one or more operations over the specified axis in the given series object.
Syntax: Series.aggregate(func, axis=0, *args, **kwargs)
Parameter :
func : Function to use for aggregating the data.
axis : Parameter needed for compatibility with DataFrame.
*args : Positional arguments to pass to func.
**kwargs : Keyword arguments to pass to func.
Returns : DataFrame, Series or scalar
Example #1: Use Series.aggregate()
function to perform aggregation on the underlying data of the given series object.
import pandas as pd
sr = pd.Series([ 34 , 5 , 13 , 32 , 4 , 15 ])
index_ = [ 'Coca Cola' , 'Sprite' , 'Coke' , 'Fanta' , 'Dew' , 'ThumbsUp' ]
sr.index = index_
print (sr)
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Output :
Coca Cola 34
Sprite 5
Coke 13
Fanta 32
Dew 4
ThumbsUp 15
dtype: int64
Now we will use Series.aggregate()
function to find the sum of all the values in the given series object.
result = sr.aggregate(func = sum )
print (result)
|
Output :
103
As we can see in the output, the Series.aggregate()
function has successfully returned the sum of the underlying data of the given series object.
Example #2 : Use Series.aggregate()
function to perform aggregation on the underlying data of the given series object.
import pandas as pd
sr = pd.Series([ 51 , 10 , 24 , 18 , 1 , 84 , 12 , 10 , 5 , 24 , 0 ])
index_ = pd.date_range( '2010-10-09 08:45' , periods = 11 , freq = 'Y' )
sr.index = index_
print (sr)
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Output :
2010-12-31 08:45:00 51
2011-12-31 08:45:00 10
2012-12-31 08:45:00 24
2013-12-31 08:45:00 18
2014-12-31 08:45:00 1
2015-12-31 08:45:00 84
2016-12-31 08:45:00 12
2017-12-31 08:45:00 10
2018-12-31 08:45:00 5
2019-12-31 08:45:00 24
2020-12-31 08:45:00 0
Freq: A-DEC, dtype: int64
Now we will use Series.aggregate()
function to find the maximum of all the values in the given series object.
result = sr.aggregate(func = max )
print (result)
|
Output :
84
As we can see in the output, the Series.aggregate()
function has successfully returned the maximum of all the values in the given series object.
Last Updated :
27 Feb, 2019
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