Sometimes while programming, we can face a problem in which we need to perform consecutive element concatenation. This problem can occur at times of school programming or competitive programming. Let’s discuss certain ways in which this problem can be solved.
Method #1 : Using list comprehension + zip()
Combination of above functionalities can be used to solve this problem. In this, we iterate the list using list comprehension and formation of pairs using zip().
# Python3 code to demonstrate working of # Consecutive element pairing in list # using list comprehension + zip() # initialize list test_list = ["G", "F", "G", "I", "S", "B", "E", "S", "T"] # printing original list print("The original list : " + str(test_list)) # Consecutive element pairing in list # using list comprehension + zip() res = [i + j for i, j in zip(test_list, test_list[1:])] # printing result print("List after Consecutive concatenation is : " + str(res)) |
The original list : [‘G’, ‘F’, ‘G’, ‘I’, ‘S’, ‘B’, ‘E’, ‘S’, ‘T’]
List after Consecutive concatenation is : [‘GF’, ‘FG’, ‘GI’, ‘IS’, ‘SB’, ‘BE’, ‘ES’, ‘ST’]
Method #2 : Using map() + concat()
The combination of these functions can also perform this task. In this traversal logic is done by map() and concat performs the task of pairing. It’s more efficient than above method.
# Python3 code to demonstrate working of # Consecutive element pairing in list # using map() + concat import operator # initialize list test_list = ["G", "F", "G", "I", "S", "B", "E", "S", "T"] # printing original list print("The original list : " + str(test_list)) # Consecutive element pairing in list # using map() + concat res = list(map(operator.concat, test_list[:-1], test_list[1:])) # printing result print("List after Consecutive concatenation is : " + str(res)) |
The original list : [‘G’, ‘F’, ‘G’, ‘I’, ‘S’, ‘B’, ‘E’, ‘S’, ‘T’]
List after Consecutive concatenation is : [‘GF’, ‘FG’, ‘GI’, ‘IS’, ‘SB’, ‘BE’, ‘ES’, ‘ST’]
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