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Python | Operation to each element in list

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  • Last Updated : 13 May, 2020

Given a list, we always come across situations in which we require to apply certain function to each element in a list. This can be easily done by applying a loop and performing an operation to each element. But having shorthands to solve this problem is always beneficial and helps to focus more on important aspects of problem. Let’s discuss certain ways in which each element of list can be operated.

Method #1 : Using list comprehension
This method performs the same task in the background as done by the looping constructs. The advantage this particular method provides is that this is a one liner and also improves code readability.




# Python3 code to demonstrate 
# operations on each list element
# using list comprehension
  
# initializing list 
test_list = ["geeks", "for", "geeks", "is", "best"]
  
# printing original list
print ("The original list is : " + str(test_list))
  
# operations on each list element
# using list comprehension
# uppercasing each element
res = [i.upper() for i in test_list]
  
# printing result
print ("The uppercased list is : " + str(res))

Output:

The original list is : ['geeks', 'for', 'geeks', 'is', 'best']
The uppercased list is : ['GEEKS', 'FOR', 'GEEKS', 'IS', 'BEST']

 
Method #2 : Using map()
Using map function, one can easily associate an element with the operation one wishes to perform. This is the most elegant way to perform or solve this kind of problems.




# Python3 code to demonstrate 
# operations on each list element
# using map()
  
# initializing list 
test_list = ["Geeks", "foR", "gEEks", "IS", "bEST"]
  
# printing original list
print ("The original list is : " + str(test_list))
  
# operations on each list element
# using map()
# lowercasing each element
res = list(map(str.lower, test_list))
  
# printing result
print ("The lowercased list is : " + str(res))

Output:

The original list is : ['Geeks', 'foR', 'gEEks', 'IS', 'bEST']
The uppercased list is : ['geeks', 'for', 'geeks', 'is', 'best']

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