# Python | Numpy numpy.ndarray.__pos__()

• Last Updated : 05 Mar, 2019

With the help of numpy.ndarray.__pos__() method of Numpy, one can multiply each and every element of an array with 1. Hence, the resultant array having values same as original array.

Syntax: ndarray.__pos__(\$self, /)

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Return: +self

Example #1 :
In this example we can see that after applying `numpy.__pos__()`, we get the simple array that can be the same as original.

 `# import the important module in python``import` `numpy as np`` ` `# make an array with numpy``gfg ``=` `np.array([``1``, ``-``2``, ``3``, ``4``, ``5``, ``6``])`` ` `# applying numpy.__pos__() method``print``(gfg.__pos__())`
Output:
```[ 1 -2  3  4  5  6]
```

Example #2 :

 `# import the important module in python``import` `numpy as np`` ` `# make an array with numpy``gfg ``=` `np.array([[``1``, ``2``, ``-``3``, ``4``, ``5``, ``6``],``                ``[``-``6``, ``5``, ``4``, ``3``, ``2``, ``-``1``]])`` ` `# applying numpy.__pos__() method``print``(gfg.__pos__())`
Output:
```[[ 1  2 -3  4  5  6]
[-6  5  4  3  2 -1]]
```

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