# Python | Numpy numpy.ndarray.__le__()

• Last Updated : 05 Mar, 2019

With the help of numpy.ndarray.__le__() method of Numpy, We can find that which element in an array is less then or equal to the value which is provided in the parameter. It will return you numpy array with boolean type having only values True and False.

Syntax: ndarray.__le__(\$self, value, /)

Return: self<=value

Example #1 :
In this example we can see that after applying `numpy.__le__()`, we get the simple boolean array that can tell us which element in an array is less than or equal to that of provided parameter.

 `# import the important module in python``import` `numpy as np`` ` `# make an array with numpy``gfg ``=` `np.array([``1``, ``2``, ``3``, ``4``, ``5``, ``6``])`` ` `# applying numpy.__le__() method``print``(gfg.__le__(``4``))`

Output:

```[ True  True  True  True False False]
```

Example #2 :

 `# import the important module in python``import` `numpy as np`` ` `# make an array with numpy``gfg ``=` `np.array([[``1``, ``2``, ``3``, ``4``, ``5``, ``6``],``                ``[``6``, ``5``, ``4``, ``3``, ``2``, ``1``]])`` ` `# applying numpy.__le__() method``print``(gfg.__le__(``4``))`

Output:

```[[ True  True  True  True False False]
[False False  True  True  True  True]]
```
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