# Python | Numpy numpy.matrix.any()

• Last Updated : 08 Apr, 2019

With the help of `Numpy numpy.matrix.any()` method, we are able to compare each and every element of one matrix with another or we can provide the axis on the we want to apply comparison if any of the element matches it return true.

Syntax : `numpy.matrix.any()`

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Return : Return true if any match found else false

Example #1 :
In this example we can see that with the help of `matrix.any()` method, we are able to compare any two matrix having different dimensions and if any match found then return true.

 `# import the important module in python``import` `numpy as np``         ` `# make a matrix with numpy``gfg1 ``=` `np.matrix(``'[1, 2, 3, 4]'``)``gfg2 ``=` `np.matrix(``'[1, 2]'``)``         ` `# applying matrix.any() method``geeks ``=` `(gfg1 ``=``=` `gfg2).``any``()``   ` `print``(geeks)`
Output:
```True
```

Example #2 :

 `# import the important module in python``import` `numpy as np``         ` `# make a matrix with numpy``gfg1 ``=` `np.matrix(``'[1, 2, 3; 4, 5, 6; 7, 8, 9]'``)``gfg2 ``=` `np.matrix(``'[1, 2, 3]'``)``         ` `# applying matrix.any() method``geeks ``=` `(gfg1 ``=``=` `gfg2).``any``()``   ` `print``(geeks)`
Output:
```True
```

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