Python | Numpy numpy.matrix.all()
Last Updated :
08 Apr, 2019
With the help of Numpy numpy.matrix.all()
method, we are able to compare each and every element of one matrix with another or we can provide the axis on the we want to apply comparison.
Syntax : numpy.matrix.all()
Return : Return true if found match else false
Example #1 :
In this example we can see that with the help of matrix.all()
method, we are able to compare any two matrix having different dimensions.
import numpy as np
gfg1 = np.matrix( '[1, 2, 3, 4]' )
gfg2 = np.matrix( '[1, 2, 3, 4]' )
geeks = (gfg1 = = gfg2). all ()
print (geeks)
|
Example #2 :
import numpy as np
gfg1 = np.matrix( '[1, 2, 3; 4, 5, 6; 7, 8, 9]' )
gfg2 = np.matrix( '[1, 2, 3]' )
geeks = (gfg1 = = gfg2). all ()
print (geeks)
|
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