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# Python | Numpy numpy.matrix.all()

With the help of `Numpy numpy.matrix.all()` method, we are able to compare each and every element of one matrix with another or we can provide the axis on the we want to apply comparison.

Syntax : `numpy.matrix.all()`

Return : Return true if found match else false

Example #1 :
In this example we can see that with the help of `matrix.all()` method, we are able to compare any two matrix having different dimensions.

 `# import the important module in python``import` `numpy as np``         ` `# make a matrix with numpy``gfg1 ``=` `np.matrix(``'[1, 2, 3, 4]'``)``gfg2 ``=` `np.matrix(``'[1, 2, 3, 4]'``)``         ` `# applying matrix.all() method``geeks ``=` `(gfg1 ``=``=` `gfg2).``all``()``   ` `print``(geeks)`

Output:

```True
```

Example #2 :

 `# import the important module in python``import` `numpy as np``         ` `# make a matrix with numpy``gfg1 ``=` `np.matrix(``'[1, 2, 3; 4, 5, 6; 7, 8, 9]'``)``gfg2 ``=` `np.matrix(``'[1, 2, 3]'``)``         ` `# applying matrix.all() method``geeks ``=` `(gfg1 ``=``=` `gfg2).``all``()``   ` `print``(geeks)`

Output:

```False
```
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