Given a list, print the number of numbers in the given range.
Examples:
Input : [10, 20, 30, 40, 50, 40, 40, 60, 70] range: 40-80 Output : 6 Input : [10, 20, 30, 40, 50, 40, 40, 60, 70] range: 10-40 Output : 4
Multiple Line Approach:
Traverse in the list and check for every number. If the number lies in the specified range, then increase the counter. At the end of traversal, the value of the counter will be the answer for the number of numbers in specified range.
Below is the Python implementation of the above approach
# Python program to count the # number of numbers in a given range # using traversal and mutliple line code def count(list1, l, r): c = 0 # traverse in the list1 for x in list1: # condition check if x>= l and x<= r: c+= 1 return c # driver code list1 = [10, 20, 30, 40, 50, 40, 40, 60, 70] l = 40r = 80 print count(list1, l, r) |
Output:
6
Single Line Approach:
We can write a single line for traversal and checking condition together:
x for x in list1 if l <= x <= r
The return value(true) of the condition check is stored in a list, and at the end the length of the list returns the answer.
Below is the Python implementation of the above approach
# Python program to count the # number of numbers in a given range def count(list1, l, r): # x for x in list1 is same as traversal in the list # the if condition checks for the number of numbers in the range # l to r # the return is stored in a list # whose length is the answer return len(list(x for x in list1 if l <= x <= r)) # driver code list1 = [10, 20, 30, 40, 50, 40, 40, 60, 70] l = 40r = 80 print count(list1, l, r) |
Output:
6
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