Python | Nth tuple index Subtraction by K

Many times, while working with records, we can have a problem in which we need to change the value of tuple elements. This is a common problem while working with tuples. Let’s discuss certain ways in which K can be subtracted to Nth element of tuple in list.

Method #1 : Using loop
Using loops this task can be performed. In this, we just iterate the list to change the Nth element by predefined value K in code.

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# Python3 code to demonstrate working of
# Nth tuple element Subtraction by K
# Using loop
  
# Initializing list
test_list = [(4, 5, 6), (7, 4, 2), (9, 10, 11)]
  
# printing original list
print("The original list is : " + str(test_list))
  
# Initializing N 
N = 1
  
# Initializing K 
K = 3
  
# Nth tuple element Subtraction by K
# Using loop
res = []
for i in range(0, len(test_list)):
    res.append((test_list[i][0], test_list[i][N] - K, test_list[i][2]))
  
# printing result
print("The tuple after removing K from Nth element : " + str(res))

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Output :

The original list is : [(4, 5, 6), (7, 4, 2), (9, 10, 11)]
The tuple after removing K from Nth element : [(4, 2, 6), (7, 1, 2), (9, 7, 11)]

 

Method #2 : Using list comprehension
This method is having the same approach as the above method, just reduces lines of code using list comprehension functionality to make code compact by size.

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# Python3 code to demonstrate working of
# Nth tuple element Subtraction by K
# Using list comprehension
  
# Initializing list
test_list = [(4, 5, 6), (7, 4, 2), (9, 10, 11)]
  
# printing original list
print("The original list is : " + str(test_list))
  
# Initializing N 
N = 1
  
# Initializing K 
K = 3
  
# Nth tuple element Subtraction by K
# Using list comprehension
res = [(a, b - K, c) for a, b, c in test_list]
  
# printing result
print("The tuple after removing K from Nth element : " + str(res))

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Output :

The original list is : [(4, 5, 6), (7, 4, 2), (9, 10, 11)]
The tuple after removing K from Nth element : [(4, 2, 6), (7, 1, 2), (9, 7, 11)]



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