# Python | Nested Tuples Subtraction

Sometimes, while working with records, we can have a problem in which we require to perform index wise subtraction of tuple elements. This can get complicated with tuple elements to be tuple and inner elements again be tuple. Letâ€™s discuss certain ways in which this problem can be solved.

**Method #1 : Using zip() + nested generator expression**

The combination of above functions can be used to perform the task. In this, we combine the elements across tuples using zip(). The iterations and difference logic is provided by generator expression.

`# Python3 code to demonstrate working of` `# Nested Tuples Subtraction` `# using zip() + nested generator expression` ` ` `# initialize tuples` `test_tup1 ` `=` `((` `1` `, ` `3` `), (` `4` `, ` `5` `), (` `2` `, ` `9` `), (` `1` `, ` `10` `))` `test_tup2 ` `=` `((` `6` `, ` `7` `), (` `3` `, ` `9` `), (` `1` `, ` `1` `), (` `7` `, ` `3` `))` ` ` `# printing original tuples` `print` `(` `"The original tuple 1 : "` `+` `str` `(test_tup1))` `print` `(` `"The original tuple 2 : "` `+` `str` `(test_tup2))` ` ` `# Nested Tuples Subtraction` `# using zip() + nested generator expression` `res ` `=` `tuple` `(` `tuple` `(a ` `-` `b ` `for` `a, b ` `in` `zip` `(tup1, tup2))\` ` ` `for` `tup1, tup2 ` `in` `zip` `(test_tup1, test_tup2))` ` ` `# printing result` `print` `(` `"The resultant tuple after subtraction : "` `+` `str` `(res))` |

**Output :**

The original tuple 1 : ((1, 3), (4, 5), (2, 9), (1, 10)) The original tuple 2 : ((6, 7), (3, 9), (1, 1), (7, 3)) The resultant tuple after subtraction : ((-5, -4), (1, -4), (1, 8), (-6, 7))

**Method #2 : Using isinstance() + zip() + loop + list comprehension**

The combination of above functions can be used to perform this particular task. In this, we check for the nesting type and perform recursion. This method can give flexibility of more than 1 level nesting.

`# Python3 code to demonstrate working of` `# Nested Tuples Subtraction` `# using isinstance() + zip() + loop + list comprehension` ` ` `# function to perform task ` `def` `tup_diff(tup1, tup2):` ` ` `if` `isinstance` `(tup1, (` `list` `, ` `tuple` `)) ` `and` `isinstance` `(tup2, (` `list` `, ` `tuple` `)):` ` ` `return` `tuple` `(tup_diff(x, y) ` `for` `x, y ` `in` `zip` `(tup1, tup2))` ` ` `return` `tup1 ` `-` `tup2` ` ` `# initialize tuples` `test_tup1 ` `=` `((` `1` `, ` `3` `), (` `4` `, ` `5` `), (` `2` `, ` `9` `), (` `1` `, ` `10` `))` `test_tup2 ` `=` `((` `6` `, ` `7` `), (` `3` `, ` `9` `), (` `1` `, ` `1` `), (` `7` `, ` `3` `))` ` ` `# printing original tuples` `print` `(` `"The original tuple 1 : "` `+` `str` `(test_tup1))` `print` `(` `"The original tuple 2 : "` `+` `str` `(test_tup2))` ` ` `# Nested Tuples Subtraction` `# using isinstance() + zip() + loop + list comprehension` `res ` `=` `tuple` `(tup_diff(x, y) ` `for` `x, y ` `in` `zip` `(test_tup1, test_tup2))` ` ` `# printing result` `print` `(` `"The resultant tuple after subtraction : "` `+` `str` `(res))` |

**Output :**

The original tuple 1 : ((1, 3), (4, 5), (2, 9), (1, 10)) The original tuple 2 : ((6, 7), (3, 9), (1, 1), (7, 3)) The resultant tuple after subtraction : ((-5, -4), (1, -4), (1, 8), (-6, 7))

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