python | Nested List Intersection Matrix Product

The problem of finding the common elements in list of 2 lists is quite a common problem and can be dealt with ease and also has been discussed before many times. But sometimes, we require to find the elements that are in common from N lists and return their product. Let’s discuss certain ways in which this operation can be performed.

Method #1 : Using reduce() + lambda + set() + loop
This particular task can be achieved in just a one line using the combination of the above functions. The reduce function can be used to operate the function of “&” operation to all the list. The set function can be used to convert list into a set to remove repetition. The task of performing product is done using loop.

filter_none

edit
close

play_arrow

link
brightness_4
code

# Python code to demonstrate 
# Nested List Intersection Matrix Product
# using reduce() + lambda + set() + loop
  
# getting Product 
def prod(val) : 
    res = 1 
    for ele in val: 
        res *= ele 
    return res  
  
# initializing list of lists
test_list = [[2, 3, 5, 8], [2, 6, 7, 3], [10, 9, 2, 3]]
  
# printing original list
print ("The original list is : " + str(test_list))
  
# Nested List Intersection Matrix Product
# using reduce() + lambda + set() + loop
res = prod(list(reduce(lambda i, j: i & j, (set(x) for x in test_list))))
  
# printing result
print ("The common row elements product is : " + str(res))

chevron_right


Output :

The original list is : [[2, 3, 5, 8], [2, 6, 7, 3], [10, 9, 2, 3]]
The common row elements product is : 6

 

Method #2 : Using map() + intersection() + loop
The map function can be used to convert each of the lists to set to be operated by to perform the intersection, using the set.intersection function. This is the most elegant way to perform this particular task. The task of performing product is done using loop.



filter_none

edit
close

play_arrow

link
brightness_4
code

# Python3 code to demonstrate 
# Nested List Intersection Matrix Product
# using map() + intersection() + loop
  
# getting Product 
def prod(val) : 
    res = 1 
    for ele in val: 
        res *= ele 
    return res  
  
# initializing list of lists
test_list = [[2, 3, 5, 8], [2, 6, 7, 3], [10, 9, 2, 3]]
  
# printing original list
print ("The original list is : " + str(test_list))
  
# Common Row elements Summation
# using map() + intersection() + loop
res = prod(list(set.intersection(*map(set, test_list))))
  
# printing result
print ("The common row elements product is : " + str(res))

chevron_right


Output :

The original list is : [[2, 3, 5, 8], [2, 6, 7, 3], [10, 9, 2, 3]]
The common row elements product is : 6

Attention geek! Strengthen your foundations with the Python Programming Foundation Course and learn the basics.

To begin with, your interview preparations Enhance your Data Structures concepts with the Python DS Course.




My Personal Notes arrow_drop_up

Check out this Author's contributed articles.

If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.


Article Tags :

Be the First to upvote.


Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.