Given a list and two elements, *x* and *y* find the nearest occurrence index of element *x* from element *y*.

Input: test_list = [2, 4, 5, 7, 8, 6, 3, 8, 7, 2, 0, 9, 4, 9, 4], x = 4, y = 6Output: 1Explanation: 4 is found at 1, 12 and 14th index, 6 is at 5th index, nearest is 1st index.

Input: test_list = [2, 4, 5, 7, 8, 6, 3, 8, 7, 2, 0, 9, 4, 9, 4], x = 7, y = 6Output: 3Explanation: 7 is found at 3rd and 8th index, 6 is at 5th index, nearest is 3rd index.

**Method : Using list comprehension + loop + index()**

In this, we find all indices of *y* using list comprehension, and then get index of *x* using *index()*, post that loop is used to get index difference, the nearest index is returned as result.

## Python3

`# Python3 code to demonstrate working of` `# Nearest occurrence of x from y in List` `# Using list comprehension + loop + index()` ` ` ` ` `# function to find index of nearest` `# occurance between two elements` `def` `nearestOccuranceIndex(test_list, x, y):` ` ` ` ` `# checking if both elements are present in list` ` ` `if` `x ` `not` `in` `test_list ` `or` `y ` `not` `in` `test_list:` ` ` `return` `-` `1` ` ` `# getting indices of x` ` ` `x_idx ` `=` `[idx ` `for` `idx ` `in` `range` `(` `len` `(test_list)) ` `if` `test_list[idx] ` `=` `=` `x]` ` ` ` ` `# getting y index` ` ` `y_idx ` `=` `test_list.index(y)` ` ` ` ` `# getting min_dist index` ` ` `min_dist ` `=` `1000000` ` ` `res ` `=` `None` ` ` `for` `ele ` `in` `x_idx:` ` ` ` ` `# checking for min ele, and updating index` ` ` `if` `abs` `(ele ` `-` `y_idx) < min_dist:` ` ` `res ` `=` `ele` ` ` `min_dist ` `=` `abs` `(ele ` `-` `y_idx)` ` ` `return` `res` ` ` ` ` `# initializing list` `input_list ` `=` `[` `2` `, ` `4` `, ` `5` `, ` `7` `, ` `8` `, ` `6` `, ` `3` `, ` `8` `, ` `4` `, ` `2` `, ` `0` `, ` `9` `, ` `4` `, ` `9` `, ` `4` `]` ` ` `# printing original list` `print` `(` `"The original list is : "` `+` `str` `(input_list))` ` ` `# initializing x` `x ` `=` `4` ` ` `# initializing y` `y ` `=` `6` ` ` `# printing result` `print` `(` `"Minimum distance index: "` `, nearestOccuranceIndex(input_list, x, y))` |

**Output:**

The original list is : [2, 4, 5, 7, 8, 6, 3, 8, 4, 2, 0, 9, 4, 9, 4]

Minimum distance index: 8

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