# Python – Mutiple Column Sort in Tuples

Sometimes, while working with records, we can have a problem in which we need to perform sort operation on one of the columns, and on other column, if equal elements, opposite sort. This kind of problem can occur as application in many domains such as web development. Lets discuss certain ways in which this problem can be solved.

Input : test_list = [(6, 7), (6, 5), (6, 4), (7, 10)]
Output : [(7, 10), (6, 4), (6, 5), (6, 7)]

Input : test_list = [(10, 7), (8, 5)]
Output : [(10, 7), (8, 5)]

Method #1 : Using `sorted() + lambda`
The combination of above functions can offer one of the ways to solve this problem. In this, we perform sort using sorted() and order and column manipulation is handled by lambda function.

 `# Python3 code to demonstrate working of  ` `# Mutiple Column Sort in Tuples ` `# Using sorted() + lambda ` ` `  `# initializing list ` `test_list ``=` `[(``6``, ``7``), (``6``, ``5``), (``1``, ``4``), (``8``, ``10``)] ` ` `  `# printing original list ` `print``(``"The original list is : "` `+` `str``(test_list)) ` ` `  `# Mutiple Column Sort in Tuples ` `# Using sorted() + lambda ` `res ``=` `sorted``(test_list, key ``=` `lambda` `sub: (``-``sub[``0``], sub[``1``])) ` ` `  `# printing result  ` `print``(``"The sorted records : "` `+` `str``(res))  `

Output :

```The original list is : [(6, 7), (6, 5), (1, 4), (8, 10)]
The sorted records : [(8, 10), (6, 5), (6, 7), (1, 4)]
```

Method #2 : Using `itemgetter() + sorted()`
This is yet another way in which this task can be performed. In this, we perform the task required for lambda function using itemgetter().

 `# Python3 code to demonstrate working of  ` `# Mutiple Column Sort in Tuples ` `# Using itemgetter() + sorted() ` `from` `operator ``import` `itemgetter ` ` `  `# initializing list ` `test_list ``=` `[(``6``, ``7``), (``6``, ``5``), (``1``, ``4``), (``8``, ``10``)] ` ` `  `# printing original list ` `print``(``"The original list is : "` `+` `str``(test_list)) ` ` `  `# Mutiple Column Sort in Tuples ` `# Using itemgetter() + sorted() ` `res ``=` `sorted``(test_list, key ``=` `itemgetter(``1``)) ` `res ``=` `sorted``(res, key ``=` `itemgetter(``0``), reverse ``=` `True``) ` ` `  `# printing result  ` `print``(``"The sorted records : "` `+` `str``(res))  `

Output :

```The original list is : [(6, 7), (6, 5), (1, 4), (8, 10)]
The sorted records : [(8, 10), (6, 5), (6, 7), (1, 4)]
```

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