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Python – Mutiple Column Sort in Tuples
  • Last Updated : 02 Jun, 2020

Sometimes, while working with records, we can have a problem in which we need to perform sort operation on one of the columns, and on other column, if equal elements, opposite sort. This kind of problem can occur as application in many domains such as web development. Lets discuss certain ways in which this problem can be solved.

Input : test_list = [(6, 7), (6, 5), (6, 4), (7, 10)]
Output : [(7, 10), (6, 4), (6, 5), (6, 7)]

Input : test_list = [(10, 7), (8, 5)]
Output : [(10, 7), (8, 5)]

Method #1 : Using sorted() + lambda
The combination of above functions can offer one of the ways to solve this problem. In this, we perform sort using sorted() and order and column manipulation is handled by lambda function.

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# Python3 code to demonstrate working of 
# Mutiple Column Sort in Tuples
# Using sorted() + lambda
  
# initializing list
test_list = [(6, 7), (6, 5), (1, 4), (8, 10)]
  
# printing original list
print("The original list is : " + str(test_list))
  
# Mutiple Column Sort in Tuples
# Using sorted() + lambda
res = sorted(test_list, key = lambda sub: (-sub[0], sub[1]))
  
# printing result 
print("The sorted records : " + str(res)) 

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Output :



The original list is : [(6, 7), (6, 5), (1, 4), (8, 10)]
The sorted records : [(8, 10), (6, 5), (6, 7), (1, 4)]

 

Method #2 : Using itemgetter() + sorted()
This is yet another way in which this task can be performed. In this, we perform the task required for lambda function using itemgetter().

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# Python3 code to demonstrate working of 
# Mutiple Column Sort in Tuples
# Using itemgetter() + sorted()
from operator import itemgetter
  
# initializing list
test_list = [(6, 7), (6, 5), (1, 4), (8, 10)]
  
# printing original list
print("The original list is : " + str(test_list))
  
# Mutiple Column Sort in Tuples
# Using itemgetter() + sorted()
res = sorted(test_list, key = itemgetter(1))
res = sorted(res, key = itemgetter(0), reverse = True)
  
# printing result 
print("The sorted records : " + str(res)) 

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Output :

The original list is : [(6, 7), (6, 5), (1, 4), (8, 10)]
The sorted records : [(8, 10), (6, 5), (6, 7), (1, 4)]

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