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Python – Minimum identical consecutive Subarray
  • Last Updated : 11 Dec, 2019

Sometimes, while working with Python lists or in competitive programming setup, we can come across a subproblem in which we need to get an element that has the minimum consecutive occurrence. The knowledge of solution to it can be of great help and can be employed whenever required. Let’s discuss a certain way in which this task can be performed.

Using groupby() + min() + lambda

This task can be solved using a combination of above functions. In this, we group each occurrence of numbers using groupby() and get the min of it using min(). The lambda function provide utility logic to perform this task.




# Python3 code to demonstrate working of
# Minimum identical consecutive Subarray
# using groupby() + min() + lambda
from itertools import groupby
  
# initializing list
test_list = [1, 1, 1, 2, 2, 5, 5, 5, 5]
  
# printing original list
print("The original list is : " + str(test_list))
  
# Minimum identical consecutive Subarray
# using groupby() + min() + lambda
temp = groupby(test_list)
res = min(temp, key = lambda sub: len(list(sub[1])))
  
# printing result 
print("Minimum Consecutive identical Occurring number is : " + str(res[0]))
Output :
The original list is : [1, 1, 1, 2, 2, 5, 5, 5, 5]
Minimum Consecutive identical Occurring number is : 2

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