Sometimes, while working with Python lists or in competitive programming setup, we can come across a subproblem in which we need to get an element that has the minimum consecutive occurrence. The knowledge of solution to it can be of great help and can be employed whenever required. Let’s discuss a certain way in which this task can be performed.

**Using groupby() + min() + lambda**

This task can be solved using a combination of above functions. In this, we group each occurrence of numbers using groupby() and get the min of it using min(). The lambda function provide utility logic to perform this task.

`# Python3 code to demonstrate working of` `# Minimum identical consecutive Subarray` `# using groupby() + min() + lambda` `from` `itertools ` `import` `groupby` ` ` `# initializing list` `test_list ` `=` `[` `1` `, ` `1` `, ` `1` `, ` `2` `, ` `2` `, ` `5` `, ` `5` `, ` `5` `, ` `5` `]` ` ` `# printing original list` `print` `(` `"The original list is : "` `+` `str` `(test_list))` ` ` `# Minimum identical consecutive Subarray` `# using groupby() + min() + lambda` `temp ` `=` `groupby(test_list)` `res ` `=` `min` `(temp, key ` `=` `lambda` `sub: ` `len` `(` `list` `(sub[` `1` `])))` ` ` `# printing result ` `print` `(` `"Minimum Consecutive identical Occurring number is : "` `+` `str` `(res[` `0` `]))` |

**Output :**

The original list is : [1, 1, 1, 2, 2, 5, 5, 5, 5] Minimum Consecutive identical Occurring number is : 2

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