# Python – Maximum Quotient Pair in List

• Last Updated : 30 Jan, 2020

Sometimes, we need to find the specific problem of getting the pair which yields the maximum Quotient, this can be solved by sorting and getting the first and last elements of the list. But in some case, we don’t with to change the ordering of list and perform some operation in a similar list without using extra space. Let’s discuss certain ways in which this can be performed.

Method #1 : Using list comprehension + `max() + combination()` + lambda
This particular task can be performed using the combination of above functions in which we use list comprehension to bind all the functionalities and max function to get the maximum quotient, combination function finds all quotients internally and lambda function is used to compute the quotients.

 `# Python3 code to demonstrate``# Maximum Quotient Pair in List``# using list comprehension + max() + combinations() + lambda``from` `itertools ``import` `combinations`` ` `# initializing list``test_list ``=` `[``3``, ``4``, ``1``, ``7``, ``9``, ``1``]`` ` `# printing original list``print``(``"The original list : "` `+` `str``(test_list))`` ` `# using list comprehension + max() + combinations() + lambda``# Maximum Quotient Pair in List``res ``=` `max``(combinations(test_list, ``2``), key ``=` `lambda` `sub: sub[``0``] ``/``/` `sub[``1``])`` ` `# print result``print``(``"The maximum quotient pair is : "` `+` `str``(res))`

Output :

```The original list : [3, 4, 1, 7, 9, 1]
The maximum quotient pair is : (9, 1)
```

Method #2 : Using list comprehension + `nlargest() + combination()` + lambda
This method has potential of not only finding a single maximum but also k maximum quotient pairs if required and uses nlargest function instead of max function to achieve this functionality.

 `# Python3 code to demonstrate``# Maximum Quotient Pair in List``# using list comprehension + nlargest() + combinations() + lambda``from` `itertools ``import` `combinations``from` `heapq ``import` `nlargest`` ` `# initializing list``test_list ``=` `[``3``, ``4``, ``1``, ``7``, ``9``, ``1``]`` ` `# printing original list``print``(``"The original list : "` `+` `str``(test_list))`` ` `# using list comprehension + max() + combinations() + lambda``# Maximum Quotient Pair in List``# computes 2 maximum pair differences``res ``=` `nlargest(``2``, combinations(test_list, ``2``), key ``=` `lambda` `sub: sub[``0``] ``/``/` `sub[``1``])`` ` `# print result``print``(``"The maximum quotient pair is : "` `+` `str``(res))`

Output :

```The original list : [3, 4, 1, 7, 9, 1]
The maximum quotient pair is : (9, 1)
```

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