Python | Max/Min of tuple dictionary values

Sometimes, while working with data, we can have a problem in which we need to find the min/max of tuple elements that are received as values of dictionary. We may have a problem to get index wise min/max. Let’s discuss certain ways in which this particular problem can be solved.

Method #1 : Using tuple() + min()/max() + zip() + values()
The combination of above methods can be used to perform this particular task. In this, we just
zip together equi index values extracted by values() using zip(). Then find min/max value using respective function. Finally result is returned as index wise max/min values as a tuple.

filter_none

edit
close

play_arrow

link
brightness_4
code

# Python3 code to demonstrate working of
# Max / Min of tuple dictionary values
# Using tuple() + min()/max() + zip() + values()
  
# Initializing dictionary
test_dict = {'gfg' : (5, 6, 1), 'is' : (8, 3, 2), 'best' : (1, 4, 9)}
  
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
  
# Max / Min of tuple dictionary values
# Using tuple() + min()/max() + zip() + values()
res = tuple(max(x) for x in zip(*test_dict.values()))
  
# printing result
print("The maximum values from each index is : " + str(res))

chevron_right


Output :



The original dictionary is : {'is': (8, 3, 2), 'gfg': (5, 6, 1), 'best': (1, 4, 9)}
The maximum values from each index is : (8, 6, 9)

 

Method #2 : Using tuple() + map() + values() + * operator
This is yet another way in which this task can be performed. The difference is that we use map() instead of loop and * operator for zipping the values together.

filter_none

edit
close

play_arrow

link
brightness_4
code

# Python3 code to demonstrate working of
# Max / Min of tuple dictionary values
# Using tuple() + map() + values() + * operator
  
# Initializing dictionary
test_dict = {'gfg' : (5, 6, 1), 'is' : (8, 3, 2), 'best' : (1, 4, 9)}
  
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
  
# Max / Min of tuple dictionary values
# Using tuple() + map() + values() + * operator
res = tuple(map(min, *test_dict.values()))
  
# printing result
print("The minimum values from each index is : " + str(res))

chevron_right


Output :

The original dictionary is : {'is': (8, 3, 2), 'gfg': (5, 6, 1), 'best': (1, 4, 9)}
The minimum values from each index is : (1, 3, 1)


My Personal Notes arrow_drop_up

Check out this Author's contributed articles.

If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.