Python | Mathematical Median of Cumulative Records

Last Updated : 30 Jan, 2020

Sometimes, while working with Python tuple list, we can have a problem in which we need to find the median of tuple values in the list. This problem has the possible application in many domains including mathematics. Let’s discuss certain ways in which this task can be performed.

Method #1 : Using loops + "~" operator
This task can be performed in brute force manner using the combination of above functionalities. In this, we sort the list and the by using the property of “~” operator to perform negation, we access the list from front and rear after flattening, performing the required computation required for finding median.

# Python3 code to demonstrate working of 
# Mathematical Median of Cumulative Records
# Using loop + "~" operator 
  
# initializing list 
test_list = [(1, 4, 5), (7, 8), (2, 4, 10)]
  
# printing list 
print("The original list : " + str(test_list)) 
  
# Mathematical Median of Cumulative Records 
# Using loop + "~" operator 
res = []
for sub in test_list :
  for ele in sub :
    res.append(ele)
res.sort() 
mid = len(res) // 2
res = (res[mid] + res[~mid]) / 2
  
# Printing result 
print("Median of Records is : " + str(res)) 

Output :

The original list : [(1, 4, 5), (7, 8), (2, 4, 10)]
Median of Records is : 4.5

Method #2 : Using chain() + statistics.median()
This is the most generic method to perform this task. In this we directly use inbuilt function after flattening using chain() to perform the median of the flattened list.

# Python3 code to demonstrate working of 
# Mathematical Median of Cumulative Records
# Using chain() + statistics.median()
import statistics 
from itertools import chain
  
# initializing list 
test_list = [(1, 4, 5), (7, 8), (2, 4, 10)] 
  
# printing list 
print("The original list : " + str(test_list)) 
  
# Mathematical Median of Cumulative Records
# Using chain() + statistics.median()
temp = list(chain(*test_list)) 
res = statistics.median(temp) 
  
# Printing result 
print("Median of Records is : " + str(res)) 

Output :

The original list : [(1, 4, 5), (7, 8), (2, 4, 10)]
Median of Records is : 4.5

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