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Python math function | hypot()
• Last Updated : 28 Aug, 2020

hypot() function is an inbuilt math function in Python that return the Euclidean norm, .

Syntax :

hypot(x, y)

Parameters :

x and y are numerical values

Returns :

Returns a float value having Euclidean norm, sqrt(x*x + y*y).

Error :

When more then two arguments are
passed, it returns a TypeError.

Note : One has to import math module before using hypot() function.

Below is the demonstration of hypot() function :

Code #1 :

 # Python3 program for hypot() function   # Import the math moduleimport math  # Use of hypot functionprint("hypot(3, 4) : ", math.hypot(3, 4))  # Neglects the negative signprint("hypot(-3, 4) : ", math.hypot(-3, 4))  print("hypot(6, 6) : ", math.hypot(6, 6))

Output :

hypot(3, 4) :  5.0
hypot(-3, 4) :  5.0
hypot(6, 6) :  8.48528137423857


Code #2 :

 # Python3 program for error in hypot() function   # import the math moduleimport math  # Use of hypot() functionprint("hypot(3, 4, 6) : ",  math.hypot(3, 4, 6))

Output :

Traceback (most recent call last):
File "/home/d8c8612ee97dd2c763e2836de644fac1.py", line 7, in
print("hypot(3, 4, 6) : ",  math.hypot(3, 4, 6))
TypeError: hypot expected 2 arguments, got 3


Practical Application :
Given perpendicular and base of a right angle triangle find the hypotenuse.

Using Pythagorean theorem which states that the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

Hence,

 Hypotenuse = sqrt(p^2 + b^2)

Code #3 :

 # Python3 program for finding Hypotenuse# in hypot() function   # import the math modulefrom math import hypot  # Perpendicular and basep = 3b = 4  # Calculates the hypotenuseprint("Hypotenuse is:", hypot(p, b))

Output :

Hypotenuse is: 5.0


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