Python math function | hypot()
Last Updated :
29 Dec, 2022
hypot() function is an inbuilt math function in Python that return the Euclidean norm, . Syntax :
hypot(x, y)
Parameters :
x and y are numerical values
Returns :
Returns a float value having Euclidean norm, sqrt(x*x + y*y).
Error :
When more than two arguments are
passed, it returns a TypeError.
Note : One has to import math module before using hypot() function. Below is the demonstration of hypot() function : Code #1 :
Python3
import math
print ("hypot( 3 , 4 ) : ", math.hypot( 3 , 4 ))
print ("hypot( - 3 , 4 ) : ", math.hypot( - 3 , 4 ))
print ("hypot( 6 , 6 ) : ", math.hypot( 6 , 6 ))
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Output :
hypot(3, 4) : 5.0
hypot(-3, 4) : 5.0
hypot(6, 6) : 8.48528137423857
Code #2 :
Python3
import math
print ("hypot( 3 , 4 , 6 ) : ", math.hypot( 3 , 4 , 6 ))
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Output :
Traceback (most recent call last):
File "/home/d8c8612ee97dd2c763e2836de644fac1.py", line 7, in
print("hypot(3, 4, 6) : ", math.hypot(3, 4, 6))
TypeError: hypot expected 2 arguments, got 3
Practical Application : Given perpendicular and base of a right angle triangle find the hypotenuse. Using Pythagorean theorem which states that the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. Hence,
Hypotenuse = sqrt(p^2 + b^2)
Code #3 :
Python3
from math import hypot
p = 3
b = 4
print ("Hypotenuse is :", hypot(p, b))
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Output :
Hypotenuse is: 5.0
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