# Python – List of dictionaries all values Summation

• Last Updated : 01 Aug, 2020

Given a list of dictionaries, extract all the values summation.

Input : test_list = [{“Apple” : 2, “Mango” : 2, “Grapes” : 2}, {“Apple” : 2, “Mango” : 2, “Grapes” : 2}]
Output : 12
Explanation : 2 + 2 +…(6-times) = 12, sum of all values.

Input : test_list = [{“Apple” : 3, “Mango” : 2, “Grapes” : 2}, {“Apple” : 2, “Mango” : 3, “Grapes” : 3}]
Output : 15
Explanation : Summation of all values leads to 15.

Method #1 : Using loop

This is brute way in which this task can be performed. In this, we iterate for all the dictionaries from list and then perform sum of all the keys of each dictionary.

## Python3

 `# Python3 code to demonstrate working of ``# List of dictionaries all values Summation``# Using loop`` ` `# initializing lists``test_list ``=` `[{``"Gfg"` `: ``6``, ``"is"` `: ``9``, ``"best"` `: ``10``}, ``             ``{``"Gfg"` `: ``8``, ``"is"` `: ``11``, ``"best"` `: ``19``},``             ``{``"Gfg"` `: ``2``, ``"is"` `: ``16``, ``"best"` `: ``10``},``             ``{``"Gfg"` `: ``12``, ``"is"` `: ``1``, ``"best"` `: ``8``},``             ``{``"Gfg"` `: ``22``, ``"is"` `: ``6``, ``"best"` `: ``8``}]`` ` `# printing original list``print``(``"The original list : "` `+` `str``(test_list))`` ` `res ``=` `0``# loop for dictionaries``for` `sub ``in` `test_list:``    ``for` `key ``in` `sub:``         ` `        ``# summation of each key ``        ``res ``+``=` `sub[key]``     ` `# printing result ``print``(``"The computed sum : "` `+` `str``(res))`
Output
```The original list : [{'Gfg': 6, 'is': 9, 'best': 10}, {'Gfg': 8, 'is': 11, 'best': 19}, {'Gfg': 2, 'is': 16, 'best': 10}, {'Gfg': 12, 'is': 1, 'best': 8}, {'Gfg': 22, 'is': 6, 'best': 8}]
The computed sum : 148
```

Method #2 : Using sum() + values() + list comprehension

The combination of above functions can be used as one-liner alternative to solve this problem. In this, summation is performed using sum(), and values( ) is used to extract values of all dictionaries in list.

## Python3

 `# Python3 code to demonstrate working of ``# List of dictionaries all values Summation``# Using sum() + values() + list comprehension`` ` `# initializing lists``test_list ``=` `[{``"Gfg"` `: ``6``, ``"is"` `: ``9``, ``"best"` `: ``10``}, ``             ``{``"Gfg"` `: ``8``, ``"is"` `: ``11``, ``"best"` `: ``19``},``             ``{``"Gfg"` `: ``2``, ``"is"` `: ``16``, ``"best"` `: ``10``},``             ``{``"Gfg"` `: ``12``, ``"is"` `: ``1``, ``"best"` `: ``8``},``             ``{``"Gfg"` `: ``22``, ``"is"` `: ``6``, ``"best"` `: ``8``}]`` ` `# printing original list``print``(``"The original list : "` `+` `str``(test_list))`` ` `res ``=` `sum``([``sum``(``list``(sub.values())) ``for` `sub ``in` `test_list])``     ` `# printing result ``print``(``"The computed sum : "` `+` `str``(res))`
Output
```The original list : [{'Gfg': 6, 'is': 9, 'best': 10}, {'Gfg': 8, 'is': 11, 'best': 19}, {'Gfg': 2, 'is': 16, 'best': 10}, {'Gfg': 12, 'is': 1, 'best': 8}, {'Gfg': 22, 'is': 6, 'best': 8}]
The computed sum : 148
```

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