# Python – List lengths as record attribute

Last Updated : 18 Apr, 2023

Many times, while dealing with containers in any language we come across lists of tuples in different forms, tuples in themselves can have sometimes more than native datatypes and can have list as their attributes. This article talks about the lengths of list as tuple attribute. Letâ€™s discuss certain ways in which this task can be performed.

Method #1 : Using list comprehension + len() This particular problem can be solved using list comprehension combined with the len function in which we use len function to find the len of list as a tuple attribute and list comprehension to iterate through the list.

## Python3

 `# Python3 code to demonstrate` `# List lengths as record attribute` `# using list comprehension + len()`   `# initializing list` `test_list ``=` `[(``'key1'``, [``3``, ``4``, ``5``]), (``'key2'``, [``1``, ``4``, ``2``]), (``'key3'``, [``9``, ``3``])]`   `# printing original list` `print``("The original ``list` `: " ``+` `str``(test_list))`   `# using list comprehension + len()` `# List lengths as record attribute` `res ``=` `[(key, ``len``(lst)) ``for` `key, lst ``in` `test_list]`   `# print result` `print``("The ``list` `tuple` `attribute lengths ``is` `: " ``+` `str``(res))`

Output :

```The original list : [('key1', [3, 4, 5]), ('key2', [1, 4, 2]), ('key3', [9, 3])]
The list tuple attribute lengths is : [('key1', 3), ('key2', 3), ('key3', 2)]```

Time Complexity: O(n), where n is length of test_list.
Auxiliary Space: O(1)

Method #2 : Using map + lambda + len() The above problem can also be solved using the map function to extend the logic to the whole list and len function can perform the similar task as the above method.

## Python3

 `# Python3 code to demonstrate` `# List lengths as record attribute` `# using map() + lambda + len()`   `# initializing list` `test_list ``=` `[(``'key1'``, [``3``, ``4``, ``5``]), (``'key2'``, [``1``, ``4``, ``2``]), (``'key3'``, [``9``, ``3``])]`   `# printing original list` `print``("The original ``list` `: " ``+` `str``(test_list))`   `# using map() + lambda + len()` `# List lengths as record attribute` `res ``=` `list``(``map``(``lambda` `x: (x[``0``], ``len``(x[``1``])), test_list))`   `# print result` `print``("The ``list` `tuple` `attribute lengths ``is` `: " ``+` `str``(res))`

Output :

```The original list : [('key1', [3, 4, 5]), ('key2', [1, 4, 2]), ('key3', [9, 3])]
The list tuple attribute lengths is : [('key1', 3), ('key2', 3), ('key3', 2)]```

Time Complexity: O(n*n), where n is the length of the input list. This is because weâ€™re using the map + lambda + len() which has a time complexity of O(n*n) in the worst case.
Auxiliary Space: O(n), as weâ€™re using additional space res other than the input list itself with the same size of input list.

Method #3: Using a for loop

## Python3

 `# initializing list` `test_list ``=` `[(``'key1'``, [``3``, ``4``, ``5``]), (``'key2'``, [``1``, ``4``, ``2``]), (``'key3'``, [``9``, ``3``])]`   `# printing original list` `print``(``"The original list : "` `+` `str``(test_list))`   `# using for loop` `res ``=` `[]` `for` `key, lst ``in` `test_list:` `    ``res.append((key, ``len``(lst)))`   `# print result` `print``(``"The list tuple attribute lengths is : "` `+` `str``(res))`

Output

```The original list : [('key1', [3, 4, 5]), ('key2', [1, 4, 2]), ('key3', [9, 3])]
The list tuple attribute lengths is : [('key1', 3), ('key2', 3), ('key3', 2)]```

Time complexity: O(n), where n is the length of the input list of tuples. This is because we are iterating over each tuple in the list once.
Auxiliary space: O(n), where n is the length of the input list of tuples. This is because we are creating a new list to store the results, which has the same length as the input list.

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