Given an array and a range [lowVal, highVal], partition the array around the range such that array is divided in three parts.
1) All elements smaller than lowVal come first.
2) All elements in range lowVal to highVal come next.
3) All elements greater than highVal appear in the end.
The individual elements of three sets can appear in any order.
Input: arr = [1, 14, 5, 20, 4, 2, 54, 20, 87, 98, 3, 1, 32] lowVal = 14, highVal = 20 Output: arr = [1, 5, 4, 2, 3, 1, 14, 20, 20, 54, 87, 98, 32] Input: arr = [1, 14, 5, 20, 4, 2, 54, 20, 87, 98, 3, 1, 32] lowVal = 20, highVal = 20 Output: arr = [1, 14, 5, 4, 2, 3, 1, 20, 20, 54, 87, 98, 32]
We have existing solution for this problem please refer Three way partitioning of an array around a given range link. We can solve this problem quickly in python using List Comprehension. Approach is simple,
- Separate list in three parts, first one will contain elements less than lowVal, second will contain elements between lowVal and highVal, third will contain elements greater than highVal.
- Concatenate all three parts together.
[1, 5, 4, 2, 3, 1, 14, 20, 20, 54, 87, 98, 32]
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