# Python – K difference Consecutive elements

• Last Updated : 01 Aug, 2020

Given a list of integer elements, check for each element if its difference with successive element is K.

Input : test_list = [5, 6, 3, 2, 5, 3, 4], K = 1
Output : [True, False, True, False, False, True]
Explanation : 5, 6; 3, 2; and 3, 4 have 1 diff. between them.

Input : test_list = [5, 6, 3, 2, 5, 3, 4], K = 2
Output : [False, False, False, False, True, False]
Explanation : Only 5, 3 has 2 diff between it.

Method #1 : Using list comprehension

This is one of the ways in which this task can be performed. In this, we check for each element with next one, if difference is K then we tag it True, else False.

## Python3

 `# Python3 code to demonstrate working of ``# K difference Consecutive elements``# Using list comprehension`` ` `# initializing list``test_list ``=` `[``5``, ``6``, ``3``, ``2``, ``5``, ``3``, ``4``]`` ` `# printing original list``print``(``"The original list : "` `+` `str``(test_list))`` ` `# initializing K ``K ``=` `3`` ` `# using list comprehension and abs() to compute result``res ``=` `[``True` `if` `abs``(test_list[idx] ``-` `test_list[idx ``+` `1``]) ``=``=` `K ``else` `False``       ``for` `idx ``in` `range``(``len``(test_list) ``-` `1``)]``     ` `# printing result ``print``(``"The difference list result : "` `+` `str``(res))`
Output
```The original list : [5, 6, 3, 2, 5, 3, 4]
The difference list result : [False, True, False, True, False, False]
```

Method #2 : Using zip() + list comprehension

This is another way in which this task can be performed. In this the consecutive list is paired using zip() and computations run through list comprehension.

## Python3

 `# Python3 code to demonstrate working of ``# K difference Consecutive elements``# Using zip() + list comprehension`` ` `# initializing list``test_list ``=` `[``5``, ``6``, ``3``, ``2``, ``5``, ``3``, ``4``]`` ` `# printing original list``print``(``"The original list : "` `+` `str``(test_list))`` ` `# initializing K ``K ``=` `3`` ` `# using list comprehension and abs() to compute result``# zip() used to pair Consecutive elements list``res ``=` `[``abs``(a ``-` `b) ``=``=` `K ``for` `a, b ``in` `zip``(test_list, test_list[``1``:])]``     ` `# printing result ``print``(``"The difference list result : "` `+` `str``(res))`
Output
```The original list : [5, 6, 3, 2, 5, 3, 4]
The difference list result : [False, True, False, True, False, False]
```

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