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# Python | Intersection of two nested list

• Last Updated : 25 Nov, 2018

This particular article aims at achieving the task of intersecting two list, in which each element is in itself a list. This is also a useful utility as this kind of task can come in life of programmer if he is in the world of development. Lets discuss some ways to achieve this task.

Method 1 : Naive Method
This is the simplest method to achieve this task and uses the brute force approach of executing a loop and to check if one list contains similar list as of the other list.

 `# Python 3 code to demonstrate ``# find intersection of nested list``# using naive method`` ` `# initializing lists``test_list1 ``=` `[ [``1``, ``2``], [``3``, ``4``], [``5``, ``6``] ]``test_list2 ``=` `[ [``3``, ``4``], [``5``, ``7``], [``1``, ``2``] ]`` ` `# printing both lists ``print` `(``"The original list 1 : "` `+` `str``(test_list1))``print` `(``"The original list 2 : "` `+` `str``(test_list2))`` ` `# using naive method ``# to get list intersection``res_list ``=` `[]``for` `i ``in` `test_list1:``    ``if` `i ``in` `test_list2:``        ``res_list.append(i)`` ` `# printing the intersection ``print` `(``"The intersection of two lists is : "` `+` `str``(res_list))`

Output :

```The original list 1 : [[1, 2], [3, 4], [5, 6]]
The original list 2 : [[3, 4], [5, 7], [1, 2]]
The intersection of two lists is : [[1, 2], [3, 4]]
```

Method 2 : Using list comprehension
We can perform the similar task as discussed above in comparatively less no. of lines. But the method is similar as above just uses list comprehension approach to perform the task.

 `# Python 3 code to demonstrate ``# find intersection of nested list``# using list comprehension`` ` `# initializing lists``test_list1 ``=` `[ [``1``, ``2``], [``3``, ``4``], [``5``, ``6``] ]``test_list2 ``=` `[ [``3``, ``4``], [``5``, ``7``], [``1``, ``2``] ]`` ` `# printing both lists ``print` `(``"The original list 1 : "` `+` `str``(test_list1))``print` `(``"The original list 2 : "` `+` `str``(test_list2))`` ` `# using list comprehension``# to get list intersection``res_list ``=` `[i ``for` `i ``in` `test_list1 ``if` `i ``in` `test_list2]`` ` `# printing the intersection ``print` `(``"The intersection of two lists is : "` `+` `str``(res_list))`

Output :

```The original list 1 : [[1, 2], [3, 4], [5, 6]]
The original list 2 : [[3, 4], [5, 7], [1, 2]]
The intersection of two lists is : [[1, 2], [3, 4]]
```

Method 3 : Using `set() + map()` and `&`
The most efficient and recommended method to perform this task is using the combination of `set()` and `map()` to achieve it. Firstly converting inner lists to tuples using map, and outer lists to set, use of & operator can perform the set intersection and hence perform this task. Further if it is required to get in lists of list fashion, we can convert outer and inner containers back to list using `map()`.

 `# Python 3 code to demonstrate ``# find intersection of nested list``# using map() + set() + &`` ` `# initializing lists``test_list1 ``=` `[ [``1``, ``2``], [``3``, ``4``], [``5``, ``6``] ]``test_list2 ``=` `[ [``3``, ``4``], [``5``, ``7``], [``1``, ``2``] ]`` ` `# printing both lists ``print` `(``"The original list 1 : "` `+` `str``(test_list1))``print` `(``"The original list 2 : "` `+` `str``(test_list2))`` ` `# using map() + set() + &``# to get list intersection``res_set ``=` `set``(``map``(``tuple``, test_list1)) & ``set``(``map``(``tuple``, test_list2))``res_list ``=` `list``(``map``(``list``, res_set))`` ` `# printing the intersection ``print` `(``"The intersection of two lists is : "` `+` `str``(res_list))`

Output :

```The original list 1 : [[1, 2], [3, 4], [5, 6]]
The original list 2 : [[3, 4], [5, 7], [1, 2]]
The intersection of two lists is : [[1, 2], [3, 4]]
```

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